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Bunuel
Machine A, working alone at its constant rate, manufactures 280 bolts per hour, and machine B, working alone at its constant rate, manufactures 220 bolts per hour. How many hours will it take for machines A and B, working together at their respective constant rates,to manufacture 1,000 bolts?

A. 1
B. 1.3
C. 1.5
D. 1.8
E. 2
Since the efficiency of both the machines are given it boils down to -

\(\frac{1000}{(220 + 280)} = 2\) Hours, Answer must be (E)
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Bunuel
Machine A, working alone at its constant rate, manufactures 280 bolts per hour, and machine B, working alone at its constant rate, manufactures 220 bolts per hour. How many hours will it take for machines A and B, working together at their respective constant rates,to manufacture 1,000 bolts?

A. 1
B. 1.3
C. 1.5
D. 1.8
E. 2

Since the combined rate is 500 bolts per hour, then it will take 1,000/500 = 2 hours for the two machines to manufacture 1,000 bolts.

Answer: E
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In one hour total bolts made=280+220=>500 bolts
500 bolts in 1 hr
So, 1000 bolts in 2 hrs.
(E)
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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