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16 Mar 2012, 07:55
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:19) correct
25%
(02:46)
wrong
based on 4162
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Marla starts running around a circular track at the same time Nick starts walking around the same circular track. Marla completes 32 laps around the track per hour and Nick completes 12 laps around the track per hour. How many minutes after Marla and Nick begin moving will Marla have completed 4 more laps around the track than Nick?
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
16 Mar 2012, 09:26
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enigma123
Marla starts running around a circular track at the same time Nick starts walking around the same circular track. Marla completes 32 laps around the track per hour and Nick completes 12 laps around the track per hour. How many minutes after Marla and Nick begin moving will Marla have completed 4 more laps around the track than Nick?
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
How to do this guys?
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
How to do this guys?
Marla completes 32-12=20 more laps in 1 hour. Marla to complete 4 (20/5=4) more laps will need 1/5 hours, which is 12 minutes.
Answer: C.
Updated on: 17 May 2021, 07:26
Originally posted by BrentGMATPrepNow on 29 Jan 2019, 10:58.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:26, edited 1 time in total.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:26, edited 1 time in total.
Kudos
Bookmarks
enigma123
Marla starts running around a circular track at the same time Nick starts walking around the same circular track. Marla completes 32 laps around the track per hour and Nick completes 12 laps around the track per hour. How many minutes after Marla and Nick begin moving will Marla have completed 4 more laps around the track than Nick?
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
(A) 5
(B) 8
(C) 12
(D) 15
(E) 20
Let t = the time (in HOURS) that it takes Marla to complete 4 more laps than Nick.
So, after t hours, we can write: (Marla's lap count) = (Nick's lap count) + 4
Now that we have a "word equation" we need only fill in the missing information
Marla completes 32 laps per hour
We can think of 1 lap as being a unit of distance.
So, 32 laps per hour is Marla's speed.
Distance = (speed)(time)
So, after t hours, Marla's lap count = 32t
Nick completes 12 laps around the track per hour
So, after t hours, Nick's lap count = 12t
We can now plug the above values into the word equation.
We get: 32t = 12t + 4
Subtract 12t from both sides to get: 20t = 4
Solve: t = 4/20 = 1/5 HOURS
1/5 hours = 12 minutes.
Answer: C
RELATED VIDEO
may i know why are you adding 4 laps to Nick , and not to Marla, mustnt Marla be 4 laps ahead of Nick? 
like 32t+4 i know i am wrong in this case, but this is how i think about this problem and how can you equate distances if they are different 
