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19 Aug 2017, 03:32
Kudos
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From the consecutive integers -10 to 10 inclusive 20 integers are randomly chosen with repetition allowed. What is the least value of the product of the 20 integers?
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
23 Aug 2017, 07:25
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kartik0604
From the consecutive integers -10 to 10 inclusive 20 integers are randomly chosen with repetition allowed. What is the least value of the product of the 20 integers?
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
The choices have something wrong.
Actually, the choice A and the choice E are same each other.
Without consideration of choices, the least value is -10^20.
However, if we should choose one from the choices, the answer could be D. It is the lease one from possible values.
Happy Studying !!!
23 Aug 2017, 08:56
Kudos
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kartik0604
From the consecutive integers -10 to 10 inclusive 20 integers are randomly chosen with repetition allowed. What is the least value of the product of the 20 integers?
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
A (-10)^20
B (-10)^10
C 0
D (-10)^19
E (-10)^20
Posted from my mobile device
Hi,
we have to choose all 10s and ensure the combination is such that the sign becomes -ive..
\(10^{19}*(-10)..\)
or \((-10)^{19}*10= -10^{20}\)
E should be \(-10^{20}\)
