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Abhi077
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13 Sep 2019, 23:33
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80% (02:00) correct
20%
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Natasha is an avid lottery player. In the certain game she plays, she mart pick one number between 30 and 39, inclusive, one number between 40 and 49, inclusive, and one number between 50 and 59, inclusive. She believes that she will have the Pert chance °twinning if her three numbers, as a set, have the greatest number of distinct prime factors possible. According to Sara, theory which of the following sets of . three numbers should she use
A)32-48-52
B)33-42-56
C)39-40-54
D)38-49-51
E)36-42-56
A)32-48-52
B)33-42-56
C)39-40-54
D)38-49-51
E)36-42-56
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14 Sep 2019, 00:21
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Natasha is an avid lottery player. In the certain game she plays, she mart pick one number between 30 and 39, inclusive, one number between 40 and 49, inclusive, and one number between 50 and 59, inclusive. She believes that she will have the Pert chance °twinning if her three numbers, as a set, have the greatest number of distinct prime factors possible. According to Sara, theory which of the following sets of . three numbers should she use
we have to find the prime factors of the product of three number..
A)32-48-52-------\(32*48*52=(2^5)*(2^4*3)*(2^2*13)\).......the distinct prime factors only 2, 3 and 13
B)33-42-56-------\(33*42*56=(3*11)*(2*3*7)*(2^3*7)\).......the distinct prime factors are 2, 3, 7 and 11
C)39-40-54 -------\(39*40*54=(3*13)*(2^3*5)*(2*3^3)\).......the distinct prime factors only 2, 3, 5 and 13
D)38-49-51-------\(38*49*51=(2*19)*(7*7)*(3*17)\).......the distinct prime factors 2, 3, 7, 17, 19
E)36-42-56-------\(36*42*56=(2^2*3^3)*(2*3*7)*(2^3*7)\).......the distinct prime factors only 2 and 3
D
we have to find the prime factors of the product of three number..
A)32-48-52-------\(32*48*52=(2^5)*(2^4*3)*(2^2*13)\).......the distinct prime factors only 2, 3 and 13
B)33-42-56-------\(33*42*56=(3*11)*(2*3*7)*(2^3*7)\).......the distinct prime factors are 2, 3, 7 and 11
C)39-40-54 -------\(39*40*54=(3*13)*(2^3*5)*(2*3^3)\).......the distinct prime factors only 2, 3, 5 and 13
D)38-49-51-------\(38*49*51=(2*19)*(7*7)*(3*17)\).......the distinct prime factors 2, 3, 7, 17, 19
E)36-42-56-------\(36*42*56=(2^2*3^3)*(2*3*7)*(2^3*7)\).......the distinct prime factors only 2 and 3
D
14 Sep 2019, 05:27
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Abhi077
Natasha is an avid lottery player. In the certain game she plays, she mart pick one number between 30 and 39, inclusive, one number between 40 and 49, inclusive, and one number between 50 and 59, inclusive. She believes that she will have the Pert chance °twinning if her three numbers, as a set, have the greatest number of distinct prime factors possible. According to Sara, theory which of the following sets of . three numbers should she use
A)32-48-52
B)33-42-56
C)39-40-54
D)38-49-51
E)36-42-56
A)32-48-52
B)33-42-56
C)39-40-54
D)38-49-51
E)36-42-56
Discussed here: sara-is-an-avid-lottery-player-in-the-certain-game-she-plays-she-mus-216660.html?fl=similar
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
