January 21, 2019 January 21, 2019 10:00 PM PST 11:00 PM PST Mark your calendars  All GMAT Club Tests are free and open January 21st for celebrate Martin Luther King Jr.'s Birthday. January 22, 2019 January 22, 2019 10:00 PM PST 11:00 PM PST In case you didn’t notice, we recently held the 1st ever GMAT game show and it was awesome! See who won a full GMAT course, and register to the next one.
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 52344

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 01:18
Question Stats:
82% (01:28) correct 18% (02:08) wrong based on 280 sessions
HideShow timer Statistics



Board of Directors
Joined: 01 Sep 2010
Posts: 3279

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 02:11



Intern
Joined: 28 Apr 2015
Posts: 19
GMAT 1: 600 Q46 V27 GMAT 2: 630 Q47 V30

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 03:10
12 seconds for the headstart + 18 seconds for Christina to catch up.
Option D. 30 Seconds is the answer.



Intern
Joined: 28 Jan 2013
Posts: 31
Location: United States
Concentration: General Management, International Business
GPA: 3.1
WE: Information Technology (Consulting)

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 03:18
Cristina gave Nicky a head start of 36 meters.
Cristina's speed = 5 m/s Nicky's speed = 3 m/s
Since both are running in the same direction, the relative speed will be 53 = 2 m/s.
how many seconds will Nicky have run before Cristina catches up to him = time taken by Cristina to cross Nicky time taken by Cristina to cross Nicky = distance they are apart/ relative speed
36/2 = 18 seconds So Nicky will run for 18 seconds by the time Cristina catches him.
Ans : B



Manager
Joined: 27 Dec 2013
Posts: 237

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 06:59
My answer D. My explanation as follows [........................[.....................] A B C 36 mts x mts Suppose Christina and Niky meet at point C ,which is x meters away from X. Christina starts the race exactly when Nicky is at point B, which is 36 meters away from point A. X/3 = 36+X /5 => X= 54. (So, the distance from point A to point C= 36+54= 90 mts) Christina and Nicky meet a point C and from point C Christina leads the race. To cover the 90mts, Niky has to run for 90/ 3 seconds= 30 seconds (Option D) Bunuel wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Kudos for a correct solution.
_________________
Kudos to you, for helping me with some KUDOS.



CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2726
Location: India
GMAT: INSIGHT
WE: Education (Education)

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 07:52
Bunuel wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Kudos for a correct solution. Relative Distance = Head Start = 36 meters Relative Speed = CN = 53 = 3 meters per second Time = Relative Distance / Relative Speed i.e. Time = 36/2 = 18 Second Taken by Christina to catch up Nicky i.e. Time taken by Nicky to have run till then = (36/3) Time taken to make headstart + 18 (After Christina starts running to catch up with Nicky)i.e. Total time that Nicky ran = 12+18 = 30 Seconds Answer: option
_________________
Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha email: info@GMATinsight.com I Call us : +919999687183 / 9891333772 Online OneonOne Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html
ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION



CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2726
Location: India
GMAT: INSIGHT
WE: Education (Education)

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 08:00
carcass wrote: The distace between the will have decreased by 36 meters, this is our distance.
This distance is decreasing between the two at a rate of 53=2 meters per second
R*T=D > 2*T=36 > T=18 seconds
B should be the answer. Hi carcassEverything is fine but you may have read the last line of question wrong. Question is : how many seconds will Nicky have run before Cristina catches up to him?So the Total Time taken = Time taken to make Headstart of 36 meters + time taken by christina to catch up Nicky = (36/3) + 18 = 30 Second What does "headstart" mean? For me a headstart is when both starting at the same time but from different locations, i.E. Nicky starts 36 meters in front of Cristina, starting both at the same time. No?
_________________
Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha email: info@GMATinsight.com I Call us : +919999687183 / 9891333772 Online OneonOne Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html
ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION



Intern
Joined: 05 Jan 2015
Posts: 1

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 08:54
used pluging in method say t is the time for cristina to catch up with Nicky, the equation will be as under: for Nicky=N=3*t+36 for Cristina=C=5*t
@t=25, N=111 & C=125 X @t=18, N=90 & C=90 right answer ans:B



Manager
Joined: 26 Apr 2012
Posts: 85
Location: India
Concentration: Entrepreneurship, General Management
GMAT 1: 640 Q48 V29 GMAT 2: 660 Q45 V35 GMAT 3: 680 Q48 V35
GPA: 2.8
WE: Information Technology (Computer Software)

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 11:16
CristinaNickyCatching Point ...............36 meters.....................x meters
At catching point Time will be same for Cristina and Nicky
Time taken for Cristina to travel 36 + x meters = 36+x/5 > T1 Time taken for Nicky to travel x meters = x/3 > T2
Equating T1 = T2
36+x/5 = x/3 ....so x = 54 meters
So total distance traveled by Nicky including the head start (this is a trap) = 36 + 54 = 90 Meters
Hence, time taken by Nicky to travel 90 meters = 90/3 = 30 Seconds
Ans D



Retired Moderator
Joined: 29 Apr 2015
Posts: 841
Location: Switzerland
Concentration: Economics, Finance
WE: Asset Management (Investment Banking)

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
23 Jun 2015, 11:51
Bunuel wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Kudos for a correct solution. Relative Speed is 5  3 = 2 meters per second Distance to run: 36m Time to catch up: 36/2 = 18 seconds Answer B
_________________
Saving was yesterday, heat up the gmatclub.forum's sentiment by spending KUDOS!
PS Please send me PM if I do not respond to your question within 24 hours.



Intern
Joined: 28 Jan 2013
Posts: 31
Location: United States
Concentration: General Management, International Business
GPA: 3.1
WE: Information Technology (Consulting)

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
24 Jun 2015, 00:53
GMATinsight wrote: carcass wrote: The distace between the will have decreased by 36 meters, this is our distance.
This distance is decreasing between the two at a rate of 53=2 meters per second
R*T=D > 2*T=36 > T=18 seconds
B should be the answer. Hi carcassEverything is fine but you may have read the last line of question wrong. Question is : how many seconds will Nicky have run before Cristina catches up to him?So the Total Time taken = Time taken to make Headstart of 36 meters + time taken by christina to catch up Nicky = (36/3) + 18 = 30 Second What does "headstart" mean? For me a headstart is when both starting at the same time but from different locations, i.E. Nicky starts 36 meters in front of Cristina, starting both at the same time. No? Hi GMATinsightLets assume it to be a 100m race (start) 0m(Cristina) 36m(Nicky) 100m(Finish) The above positions are at the start of the race. The race ideally starts when both the contestants start the run at the same time. Given a headstart( before the race starts) of 36 meters meaning, both the contestants start to run at the same time but Nicky starts from the 36m mark and Cristina from 0m mark. So we should not count the 12 sec that Nicky took to reach 36m mark. Correct if I am missing anything. Regards, Manoj Reddy



Queens MBA Thread Master
Joined: 24 Oct 2012
Posts: 170
Concentration: Leadership, General Management

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
26 Jun 2015, 07:20
Bunuel wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Kudos for a correct solution. Since both are running in same direction, Relative speed between N and C = C's Speed  N's Speed = 53 = 2 meters per second. Now the relative distance they C has to cover is 36 meters. Hence Option B should be correct. Hence C will take 18 seconds to cover 36 meter with speed of 2 meters per second.



Manager
Joined: 01 Jan 2015
Posts: 56

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
28 Jun 2015, 09:02
Head start = 36meters;Nicky runs at a pace of only 3 meters per second> 36/3 = 12sec head start now let x be the seconds Nicky will have run before Cristina catches up to him! now catches up means same at same distance from the start ; eq = 5x=3(12+x) only 18 satisfies the equation hence x=18



Math Expert
Joined: 02 Sep 2009
Posts: 52344

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
29 Jun 2015, 05:28
Bunuel wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
(A) 15 seconds (B) 18 seconds (C) 25 seconds (D) 30 seconds (E) 45 seconds
Kudos for a correct solution. MANHATTAN GMAT OFFICIAL SOLUTION:Save time on this problem by dealing with the rate at which the distance between Cristina and Nicky changes. Nicky is originally 36 meters ahead of Cristina. If Nicky runs at a rate of 3 meters per second and Cristina runs at a rate of 5 meters per second, then the distance between the two runners is shrinking at a rate of 5  3 = 2 meters per second. You can now figure out how long it will take for Cristina to catch Nicky using a single RT = D equation. The rate at which the distance between the two runners is shrinking is 2 meters per second, and the distance is 36 meters (because thats how far apart Nicky and Cristina are): 2t = 36; t = 18. Answer: B. Attachment:
20150629_1726.png [ 4.74 KiB  Viewed 5863 times ]
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Senior Manager
Status: Math is psychological
Joined: 07 Apr 2014
Posts: 416
Location: Netherlands
GMAT Date: 02112015
WE: Psychology and Counseling (Other)

Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
30 Jun 2015, 10:23
Hello,
I like the relative rate idea, but for some reason very rarely think of using it... Anyway, this is what I did: 5T = 36 + 3T > 2T = 36 > T = 18.
So, 5T is the distance for Christina, which should be the same as the distance for Nicky, plus the extra 36 meters Nicky ran. So, we add 3T to 36, as we don't know how many minutes extra Nicky ran.



Intern
Joined: 06 May 2015
Posts: 3
Concentration: Strategy, Sustainability

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
05 Jul 2015, 03:34
For those of you getting the Ans as 30 (aka Option D) I had got that too intially but I realized I had misunderstood the question. Headstart means that Nicky and Christina started the race at THE SAME TIME but Nicky started from d point which was 36mt ahead of the point Christina started the race from. The answer would probably have been 30 if the question read : "Christina let Nicky run for 36 mt before she started running the race"



CEO
Joined: 20 Mar 2014
Posts: 2636
Concentration: Finance, Strategy
GPA: 3.7
WE: Engineering (Aerospace and Defense)

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
15 Jul 2015, 03:07
Dont overcomplicate things here.
Headstart means that total distance covered by Cristina will be 36 m more than what Nicky would cover. The only time that we need to worry about is when Cristina started the race and took to cover D+36 when D = T*3 m



CEO
Joined: 11 Sep 2015
Posts: 3355
Location: Canada

Re: How many seconds will Nicky have run before Cristina catches up to him
[#permalink]
Show Tags
16 Dec 2015, 11:04
laveen_g wrote: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky run before Cristina catches up to him? a. 15 seconds b. 18 seconds c. 25 seconds d. 30 seconds e. 45 seconds In 1 second, Nicky runs 3 meters, and Christina runs 5 meters. So, in ONE SECOND the gap between Nicky and Christina decreases by 2 meters. At the beginning, the gap between them is 36 meters. So, since (18)( 2) = 36, we can see that it will take 18 seconds for the 36meter gap to reduce to zero meters. Answer: B Cheers, Brent
_________________
Test confidently with gmatprepnow.com



Director
Joined: 20 Feb 2015
Posts: 795
Concentration: Strategy, General Management

Re: How many seconds will Nicky have run before Cristina catches up to him
[#permalink]
Show Tags
17 Dec 2015, 05:50
as given speed of Cristina =5 metres per second Speed of Nicky =3 metres per second head start =36 meters (Relative distance) relative speed =2 metres per second time taken = 36/2=18 seconds



Intern
Joined: 19 Aug 2016
Posts: 5

Re: Nicky and Cristina are running a race. Since Cristina is faster than N
[#permalink]
Show Tags
19 Sep 2016, 03:03
Why is the answer D incorrect? 18 seconds is the time for which N will run once C has started too, but what about the 36metres of headstart? i.e 36/3 , 12 seconds? So , shouldn't the total time be 12+18=30 seconds?




Re: Nicky and Cristina are running a race. Since Cristina is faster than N &nbs
[#permalink]
19 Sep 2016, 03:03



Go to page
1 2
Next
[ 22 posts ]



