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Of the 150 houses in a certain development, 60 percent have
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29 May 2017, 03:27
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Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65
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Re: Of the 150 houses in a certain development, 60 percent have
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29 May 2017, 06:24
ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 This can be solved using Venn Diagram (refer the attachment) AC = 60% of 150 = 90 Sunporch = 50% of 150 = 75 SP = 30% of 150 = 45 Using the venn diagram we can form the following equations a+b+c+d+e+f+g+h = 150 a+b+c+d+f+g = 140  (1) (as e = h = 5) Taking 1 circle at a time AC = a+b+d = 85  (2) .. (as e = 5) SunPorch = c+b+f = 70  (3) .. (as e = 5) SP = g+d+f = 40  (4) .. (as e = 5) equation (2) + (3) + (4) a+c+g+ 2(d+b+f) = 195 subtracting this with equation (1) d+b+f = 195  140 = 55 Answer option D
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Re: Of the 150 houses in a certain development, 60 percent have
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29 May 2017, 03:31



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Re: Of the 150 houses in a certain development, 60 percent have
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29 May 2017, 08:23
ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 all three = neither =5 = 10/3 % of 150 working formula : Total = AC + sunporch + swimming pool  Exactly two  2*all three + neither 100 = 60 + 50 + 30 Exactly two  2*10/3 + 10/3 100 =140  Exactly two  10/3 Exactly two = 40  10/3 = (12010)/3 = 110/3 % 110/3 % of 150 = 110*150/300 =55 Ans D



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Of the 150 houses in a certain development, 60 percent have
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28 Jun 2017, 06:54
ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 Hi Bunuel, Why formula (1) is incorrect? https://gmatclub.com/forum/advancedoverlappingsetsproblems144260.html(i) In term of percentage Total = A + B + C − (sum of 2−group overlaps) + (all three) + Neither 100 = 60 + 50 + 30  (x) + (5/150)(100) + (5/150)(100) 100 = 140 + (20/3)  x x = 40 + (20/3) x = 140/3% (x/150)(100) = (140/3) x = (140/300)(150) x = 70 (ii) In term of number Total = A + B + C − (sum of 2−group overlaps) + (all three) + Neither 150 = 90 + 75 + 45  x + 5 + 5 x = 70
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Re: Of the 150 houses in a certain development, 60 percent have
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28 Jun 2017, 06:58
hazelnut wrote: ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 Hi Bunuel, Why formula (1) is incorrect? https://gmatclub.com/forum/advancedoverlappingsetsproblems144260.htmlTotal = A + B + C − (sum of 2−group overlaps) + (all three) + Neither 100 = 60 + 50 + 30  (x) + (5/150)(100) + (5/150)(100) 100 = 140 + (20/3)  x x = 40 + (20/3) x = 140/3 We need to find exact two. The formula you have listed is for general sum of 2 group overlap. The total you have listed is 100 while in the question it is 150. Formula for exact two is: Total = A + B + C + Neither  (exact 2)  2 * (all three) 150=90+75+45+510sum of exact 2. 205150= sum of exact 2 sum of exact 2=55 D



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Re: Of the 150 houses in a certain development, 60 percent have
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07 Jul 2017, 07:32
Total = A + B +C  (exactly two)  2(all three) + none
Refer to GMAT Club math book for more details.



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Re: Of the 150 houses in a certain development, 60 percent have
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07 Oct 2017, 10:29
I can solve this problem with the appropriate formula. Is there a way to solve this problem by backsolving



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Re: Of the 150 houses in a certain development, 60 percent have
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15 Nov 2017, 17:22
ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 We can create the following equation: Total houses = number with air conditioning + number with sunporch + number with pool  number with only two of the three things  2(number with all three things) + number with none of the three things 150 = 0.6(150) + 0.5(150) + 0.3(150)  D  2(5) + 5 150 = 90 + 75 + 45  D  10 + 5 150 = 205  D D = 55 Answer: D
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Re: Of the 150 houses in a certain development, 60 percent have
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15 Nov 2017, 21:28
150= 90+75+45Both10+5
Both = 55
This is a 30% level question imo.



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Of the 150 houses in a certain development, 60 percent have
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08 May 2018, 12:40
ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 pushpitkc generis hello here is my solution ...I just need to understand what I did wrong here 60 percent have airconditioning = 90 50 percent have a sunporch = 75 30 percent have a swimming pool = 45 5 houses has all three amenities 5 houses has non of these amenities we need to find number of houses that have exactly two of the ameneties X = both so here is my equation 150 = 90+75+45(5+x)+5 ( let me explain what i did here, i summed up three groups 90+75+45 minus ( 5 houses with all three feature +houses with only both features ) +neither isnt it correct , i know it is not but why
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Of the 150 houses in a certain development, 60 percent have
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08 May 2018, 13:26
Hi dave13Attachment:
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Given: P(Neither) = 5  P(All 3) = 5 What we need to understand while solving problems like these is that P(Airconditioner) = 0.6(150) = 90 = P(Only Airconditioner) + A + B + P(All 3) P(Sunporch) = 0.5(150) = 75 = P(Only SunPorch) + A + C + P(All 3) P(SwimmingPool) = 0.3(150) = 45 = P(Only SwimmingPool) + B + C + P(All 3) P(Total) = P(Only Airconditioner) + P(Only SunPorch) + P(Only SwimmingPool) + (A + B + C) + P(All 3) 150 = 90 + 75 + 45  (A + B + C)  2*P(All 3) + 5 Therefore, the houses which have only two amenities are P(Only 2) = A + B + C = 205  150 = 55 (Option D)Hope this helps you!
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Of the 150 houses in a certain development, 60 percent have
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08 May 2018, 13:35
dave13 wrote: ganand wrote: Of the 150 houses in a certain development, 60 percent have airconditioning, 50 percent have a sunporch, and 30 percent have a swimming pool. If 5 of the houses have all three of these amenities and 5 have none of them, how many of the houses have exactly two of these amenities? (A) 10 (B) 45 (C) 50 (D) 55 (E) 65 pushpitkc generis hello here is my solution ...I just need to understand what I did wrong here 60 percent have airconditioning = 90 50 percent have a sunporch = 75 30 percent have a swimming pool = 45 5 houses has all three amenities 5 houses has non of these amenities we need to find number of houses that have exactly two of the ameneties X = both so here is my equation 150 = 90+75+45(5+x)+5 ( let me explain what i did here, i summed up three groups 90+75+45 minus ( 5 houses with all three feature +houses with only both features ) +neither isnt it correct , i know it is not but why dave13EDITpushpitkc 's answer should help. AND  your issue is addressed in warriorguy 's post HEREI am a fan of Venn diagrams. I am not a fan of Venn diagrams for three overlapping set questions, which typically involve a very specific question. Try this formula for three overlapping sets: Total = Group1 + Group 2 + Group 3  (sum of 2group overlaps)  2*(all three) + None Bunuel explains in this post, with a diagramAlso see Bunuel and VeritasPrepKarishma , here, Overlapping Sets Made EasyThe pictorial representation I can find most quickly, albeit with a different fact pattern, is here
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Of the 150 houses in a certain development, 60 percent have
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09 May 2018, 03:22
pushpitkc wrote: Hi dave13Attachment: Set(s).png Given: P(Neither) = 5  P(All 3) = 5 What we need to understand while solving problems like these is that P(Airconditioner) = 0.6(150) = 90 = P(Only Airconditioner) + A + B + P(All 3) P(Sunporch) = 0.5(150) = 75 = P(Only SunPorch) + B + C + P(All 3)P(SwimmingPool) = 0.3(150) = 45 = P(Only SwimmingPool) + B + C + P(All 3) P(Total) = P(Only Airconditioner) + P(Only SunPorch) + P(Only SwimmingPool) + (A + B + C) + P(All 3) 150 = 90 + 75 + 45  (A + B + C)  2*P(All 3) + 5 Therefore, the houses which have only two amenities are P(Only 2) = A + B + C = 205  150 = 55 (Option D)Hope this helps you! pushpitkc , generis many thanks for explanation, almost got it appreciate! pushpitkc , just one question. Didnt you make a typo here (see highlighted part of your solution above or below ) P(Airconditioner) = 0.6(150) = 90 = P(Only Airconditioner) + A + B + P(All 3) P(Sunporch) = 0.5(150) = 75 = P(Only SunPorch) + B + C + P(All 3)P(SwimmingPool) = 0.3(150) = 45 = P(Only SwimmingPool) + B + C + P(All 3) Lets start from case #1: this one one P(Airconditioner) = 0.6(150) = 90 = P(Only Airconditioner) + A + B + P(All 3) I interpert it as follows: So there are 90 houses with air conditioning among which are houses featuring only Airconditioner, OR both amenties Airconditioner+Porch and Airconditioner + Swimming pool OR three amenites. Am i understanding it correctly ? If the above mentioned information i understand correctly, then why here P(Sunporch) = 0.5(150) = 75 = P(Only SunPorch) + B + C + P(All 3) are you adding up + B + C + P(All 3) and not +A+C+(All 3) ? As per your diagram Sunporch has intersection with air conditioning and swimming pool. I am just following the pattern as in case #1. Case # 1 has intersection with A, B and P so you added A + B + P(All 3) But case # 2 has this intersection +A+C+P but you sum up B + C + P i would appreaciate if you could expain this Further to the above questions can you please confirm if the detaled solution based on suggested formula is correct pls see below \(150 = 90+75+45 (A+B+C)2(5) +5\) \(150= 210(A+B+C)10+5\) \(150= 210 ABC5\) many thanks and have a great day \(A+B+C = 55\)
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Re: Of the 150 houses in a certain development, 60 percent have
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09 May 2018, 03:44
Hi dave13You have the eyes of a hawk. You spotted the typo, which I've now edited in my solution for this problem. dave13 wrote: Lets start from case #1: this one one P(Airconditioner) = 0.6(150) = 90 = P(Only Airconditioner) + A + B + P(All 3) I interpert it as follows: So there are 90 houses with air conditioning among which are houses featuring only Airconditioner, OR both amenties Airconditioner+Porch and Airconditioner + Swimming pool OR three amenites. Am i understanding it correctly ? Your understanding is spot on, here! The same line of reasoning for the other 2 aspects of the house  P(Sunporch) and P(SwimmingPool). It was the typo which caused the confusion Sorry about that! Also, the understanding of the final solution is perfect Hope this helps you
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Of the 150 houses in a certain development, 60 percent have
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10 May 2018, 01:59
Let a = # of houses with only one b = # of houses with two *We're solving for b. c = # of houses with all three (given: 5) d = # of houses with none (given: 5)
There are 150 houses total: a + b + c + d = 150 substitute c=5 & d=5 ==> a + b = 140. So 140 houses have either one or two amenities.
They gave us 60% + 50% + 30% = 140% so there is some overlap  some houses have multiple amenities.
Because b's are double counted and c's are triple counted, a + 2b + 3c = 150(140%) = 210 Substitute 3c = 3*5 = 15 a + 2b + 15 = 210 From above, a + b = 140. Therefore, (140) + b + 15 = 210 b = 210  155 = 55
Answer: D.



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Re: Of the 150 houses in a certain development, 60 percent have
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11 Aug 2018, 18:04
If anyone is looking for 3set Venn Diagram questions to practice on from the Official Guide, I have compiled a list at the following link: Threeset Venn DiagramsOn this question, while I would still draw the Venn Diagram myself, the key is to know the formula for threeset Venn Diagrams that has been mentioned in this thread: Total = Group1 + Group2 + Group3  (sum of 2group overlaps)  2*(all three) + None Then, all we need to do is plug in the numbers we are given (converting percents to numbers) and solve for the sum of 2group overlaps, because that is what the question is asking us for. Please let me know if you have any questions, or if you want me to post a video solution!
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