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Of the land owned by a farmer, 90 percent was cleared for planting. Of
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15 Oct 2015, 22:04
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Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own? (A) 5,832 (B) 6,480 (C) 7,200 (D) 8,000 (E) 8,889 Kudos for a correct solution.
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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15 Oct 2015, 23:14
Bunuel wrote: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own?
(A) 5,832 (B) 6,480 (C) 7,200 (D) 8,000 (E) 8,889
Kudos for a correct solution. 40% od 90% = 36%, 50% 0f 90% = 45% so the remaining 904536=9%=720 acres or 10% of 90%=9% > 720/9*100=80o0 acres Answer (D)
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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16 Oct 2015, 02:14
Percentage cleared for planting = 90 Soybean = 40% of 90 = 36 % of total Wheat = 50 % of 90 =45 % of total Corn = 10 % of 90 = 9 % of total Since 9% of total = 720 acres Therefore , total land = 720/9 * 100 = 8000 acres Answer D
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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16 Oct 2015, 02:40
IMO 8000
9 out of 100 corresponds to 720 out of 8000.



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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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16 Oct 2015, 18:52
Let farmer has X land; Cleaned =.9 x out of .9 x 10% is 720 ; therefore .09x=720 => x=8000
Hence answer is D
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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16 Oct 2015, 20:58
Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own? (A) 5,832 (B) 6,480 (C) 7,200 (D) 8,000 (E) 8,889 For this type of Question its always better to go by option and elimination plays a key role here . As per the Q  out of the total land  90% was cleared for planting . now see the option  only B,C, D will give you a integer value .When we do 90% of total Area. hence A,E can be eliminated . Option B  6480 * (90/100) = 5832 5832 * ( 40/100 ) = wont give us a integer value . Hence can be eliminated . Option C and D left . Now see option D is good number to start with because its value .( 8000) When we apply 8000( 90/100) = 7200 (50/100) = 3600 7200(40/100)= 2880 Now sum them = 2880 + 3600 = 6480 If the remaining 720 acres of cleared land was planted with corn . This remaining area comes from 7200  6480 = 720 . Hence the condition got satisfied . Ans is D .
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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02 May 2016, 08:55
Bunuel wrote: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own?
(A) 5,832 (B) 6,480 (C) 7,200 (D) 8,000 (E) 8,889
Kudos for a correct solution. Solution: We can start by letting T = the total land owned by the farmer. Since 90% was cleared for farming we can say: 0.9T = cleared for farming We are next given that of the cleared land, 40 percent was planted with soybeans. This can be represented as: 0.4(0.9T) = planted with soybeans 0.36T = planted with soybeans Next we are given that 50 percent of the cleared land was planted with wheat. This can be represented as: 0.5(0.9T) = 0.45T Finally, we are given that the remaining 720 acres of cleared land was planted with corn. Thus, we can create the following equation: 0.36T + 0.45T + 720 = 0.9T 0.81T + 720 = 0.9T 720 = 0.09T 72,000 = 9T T = 8,000 Answer: D
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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10 May 2016, 17:55
Attached is a visual that should help.
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Screen Shot 20160510 at 5.48.46 PM.png [ 67.68 KiB  Viewed 8273 times ]
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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10 May 2016, 19:58
(10% of (90% of total land)) is 720 \(0.1 * 0.9 * X = 720\) \(X = 8000\) Option D
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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21 Jun 2016, 11:12
I understand it the following way: 0.40(90)+0.50(90)+720=0.90x 2880+3600+720=0.90x 7200=0.90x \(\frac{7200}{0.90}\)=x 8000=x



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Of the land owned by a farmer, 90 percent was cleared for planting. Of
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24 Jun 2016, 04:55
Bunuel wrote: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own?
(A) 5,832 (B) 6,480 (C) 7,200 (D) 8,000 (E) 8,889
Kudos for a correct solution. Suppose the total land was 100. Then, 90% of 100 = 90. Of the 90, 40%(36) of land was used for soyabeans, 50%(45) was for wheat. Remaining land portion of 90 is 9. According to question 9 equals 720. By unitary method. If; 9(land) = 720 then; 100(land) =x(what). By cross multiplication. x = \(720*100/9\) = 8000.D.



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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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13 Nov 2016, 23:23
Hi,
Is this a right approach [or an unnecessarily longer one?]
In the cleared land : 720 is 10% Hence, 720*4 = 2880 is 40% and, 720*5 = 3600 is 50%
Adding all these the 90% cleared land turns out to be 7200, the remaining has to be 800. Hence 7200+800 = 8000 > Answer D.



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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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22 Dec 2016, 14:37
0.4 x 0.9X = 0.36X = Soybean 0.5 x 0.9X = 0.45X = Wheat 0.36x + 0.45x + 720 = 0.9x 0.81x + 720 = 0.9x x = 8000 D
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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03 Feb 2018, 16:36
Hi All, This question can be solved by TESTing THE ANSWERS. From the prompt, we know that we're going to be doing a number of small calculations AND we're going to end with 720 acres remaining for corn. Since we're asked for the total number of acres, and the answers are all numbers, we just have to work until we find the one that matches what we've been told. In these situations, it's often best to start with Answer B or D. Between those 2 options, D looks 'nicer'/easier, so let's start there. IF....there were 8000 total acres... 90% was cleared for planting = (.9)(8000) = 7200 acres for planting Of that land, 40% was soybeans = (4.)(7200) = 2880 acres 50% was wheat = (.5)(7200) = 3600 2880 + 3600 = 6480 7200  6480 = 720 > this is an exact match for what we were told, so this MUST be the answer. Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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12 May 2018, 04:26
Bunuel niks18 gmatbusters chetan2u VeritasPrepKarishmaQuote: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own? Usually in percentage problems, do not we take final value as 100 and back solve? Eg: Say total acres of farm owned = 100 Cleared for farming: 90 acres Of cleared farm: 40% ie 36 acres planted with SB Of cleared farm: 50% ie 45 acres planted with W Total SB + W : 91 acres Remaining 9 acres: planted with corn. Now 9x= 720 or x = 60 Let us set up a proportion: SB : W: C = 36 : 45 : 9 or 4 :5 : 1 or 10 * x = 600 What is incorrect about this approach ?
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Re: Of the land owned by a farmer, 90 percent was cleared for planting. Of
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12 May 2018, 04:50
36+45 =81x now remaining cleared land = 9081 = 9x Now 9x = 720: x =80 So total land = 100x = 8000 adkikani wrote: Quote: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 40 percent was planted with soybeans and 50 percent of the cleared land was planted with wheat. If the remaining 720 acres of cleared land was planted with corn, how many acres did the farmer own? Usually in percentage problems, do not we take final value as 100 and back solve? Eg: Say total acres of farm owned = 100 xCleared for farming: 90 x acres Of cleared farm: 40% ie 36 x acres planted with SB Of cleared farm: 50% ie 45 x acres planted with W Total SB + W : 91 acres  CALCULATION ERRORRemaining 9 acres: planted with corn. Now 9x= 720 or x = 60 again CALCULATION ERRORLet us set up a proportion: SB : W: C = 36 : 45 : 9 or 4 :5 : 1 or 10 * x = 600  NOT required. see my approach in last stepsWhat is incorrect about this approach ?
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