No. of students = 9
Mean = 50
Sum = 450
Median (5th term in ascending order) = 40
I. At least one student had more than 60 correct answers.
To check if there is a figure of greater than 60 (which is greater than the mean), we should maximize the terms leading up to the median
Now, since the 5th term (median) is 40, our first 4 terms can not be greater than that so maximum we can have is 40 as the first 5 terms so a sum of 200
Sum of remaining 4 terms = 450-200 = 250, so average of remaining 4 terms is 62.5 so atleast one student will have greater than 60 correct answers
II. At least one student had more than 40 and less than 50 correct answers.
Same case as in the previous statement
40 40 40 40 40 and if we have 62 63 62 63 that satisfies both mean and median and not true to have between 40 and 50 correct answers
III. At least one student had less than 40 correct answers.
Same case as in the previous statement
40 40 40 40 40 and if we have 62 63 62 63 that satisfies both mean and median and not true to have one student with less than 40 correct answers
Answer - A