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p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

Just noticed that the two statements give two different values of p: 0.300431 and 0.300254. Thus the two statements contradict each other, which never happens on the real test. Not a good question.
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p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

not sure whether my understand is rite here.. just correct me if I am wrong..

why we represent not snowing on any day as (1-p)^7 instead of P. Is that since we are calcuating for 7 days in a week?
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Bunuel
p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

not sure whether my understand is rite here.. just correct me if I am wrong..

why we represent not snowing on any day as (1-p)^7 instead of P. Is that since we are calcuating for 7 days in a week?

The probability of snowing is p, thus the probability of not snowing is 1-p.
The probability of not snowing entire week is (1-p)^7, therefore the probability of snowing on at least one day is 1-(1-p)^7.

Hope it's clear.
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p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

I have two doubts about the wording of this question:
a) When the question says "p is the probability of snow fall on any given day in the first week of December" , it means that the probability of snow fall on Monday is p, on Tuesday is p, on wednesday the same, ..., right?
b) In the statement (2), I think that "this week" is not clear. Which "this week"?, the first week of december or the current week? I don't think that a real GMAT question would use "this week". What do you think?
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p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

I have two doubts about the wording of this question:
a) When the question says "p is the probability of snow fall on any given day in the first week of December" , it means that the probability of snow fall on Monday is p, on Tuesday is p, on wednesday the same, ..., right?
b) In the statement (2), I think that "this week" is not clear. Which "this week"?, the first week of december or the current week? I don't think that a real GMAT question would use "this week". What do you think?

Please refer to the solutions above and ask if anything remains unclear.
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Statement 1: Probability of snowing on "at least 1 day" = (1 - probability of snowing on zero days). Since there is only one unknown we can rearrange the equation to solve for p. Sufficient.

Statement 2: Since .00022 is the probability of snowing everyday, p^7 must equal 0.00022. We can backsolve to get p. Sufficient.
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sanjoo
p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022


p = ?

1) 1 - q^7 = .82
q = 0.97
p = 1 - q = 0.3 => Sufficient

2) p^7 = 0.00022
p = 0.3 => Sufficient

ANSWER: D

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