Peter and Tom shared the driving on a certain trip. If Peter

Question

Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but peter on drove 2/5 of the total distance, what was the ration of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3

A. 1:5 
B. 2:5 
C. 1:2 
D. 3:5 
E. 2:3

abid1986 · Accepted Answer

As time is constant for both
Distance is directly proportional to speed

pete distance = 2/5
tom distance = 3/5

Pete distance/tom distance = pete speed/tom speed
=(2/5)/(3/5)
 pete speed/tom speed= 2:3

ashkrs · Answer

welcome to gmatclub

peter speed (2d/5)/t 
tom speed d/t

ratio = peter/tom = 2/5 => 2:5

GMAT TIGER · Answer

since the time take by each is equal, it is straight respective distances: 2:5

PareshGmat · Answer

Refer screenshot below:

Raihanuddin · Answer

Let Total Distance= 5
Peter drove= 2 mile and Tom Drove= 3 mile. Let, Each took 1 hour
Their speed = 2/1 : 3/1 = 2: 3

Salvetor · Answer

Let total distance be D.

Tom's covered distance is = 2D/5 
Tom's rate= 2D/5T

Peter's covered distance = D-2D/5 = 3D/5
Peter's rate= 3D/5T

So Tom: Peter = 2D/5T x 5T/3D 
 = 2 : 3

GMATGuruNY · Answer

Let the total distance = 5 miles, implying that Peter's distance =  \frac{2}{5} * 5 = 2  miles and that Tom's distance =  5-2 = 3  miles.
If Peter and Tom each drive for 1 hour, then Peter's speed : Tom's speed = 2 mph : 3 mph.

E

ScottTargetTestPrep · Answer

We can let the time driven by Peter and Tom = t. If we let the total distance = d, then Peter’s distance = (2/5)d = 2d/5 and Tom’s distance = (3/5)d = 3d/5.

Thus, Peter’s rate is (2d/5)/t = 2d/(5t), and Tom’s rate is (3d/5)/t = 3d/(5t).

The ratio of Peter’s average speed to Tom’s average speed is (2d/5t)/(3d/5t) = 10dt/(15dt) = 2/3.

Answer: E

twoface07 · Answer

Distance driven by Peter d (p)  = 2/5
Distance driven by Tom d (t)  = 1 - (2/5) = 3/5

Since time (T) taken is the same for Peter and Tom:

T (p)  = T (t) 
=> d (p)  / s (p)  = d (t)  / s (t) 
=> (2/5) / s (p)  = (3/5) / s (t) 
=>  s (p)  / s (t)  = (2/3) 
Answer is choice (E).

Kinshook · Answer

Asked: Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Peter's average speed to Tom's average speed?

Since time is same for both Peter and Tom
d1/d2 = s1/s2 ; 
where d1 & d2 are distance travelled by Peter and Tome respectively & 
where s1 & s2 are speed of Peter and Tome respectively
(2/5)/(1-2/5) = (2/5)/(3/5) = s1/s2
s1:s2 = 2:3

IMO E

tkorzhan1995 · Answer

Bunuel ,  GMATNinja , can you please explain why Tom cannot drive the full distance s, and should drive 3/5 of the distance? What is the trigger in the questions?

yalembagrad · Answer

If Tom drives the full distance S then Peter has nothing left to drive.

You've been given the distances both people drove in proportion to the total distance.

ArnauG · Answer

Let's assume that Peter and Tom drove for a total of "x" hours each. Since they both drove for the same amount of time, we can consider their driving time as equal.

Now, if Peter only drove 2/5 of the total distance, it means that Tom drove the remaining 3/5 of the distance.

Let's say the total distance of the trip is "d". Since Peter drove 2/5 of the distance, his driving distance would be (2/5)*d, and Tom's driving distance would be (3/5)*d.

Now, let's calculate the average speed for each of them.

Peter's average speed = Peter's driving distance / Peter's driving time = (2/5)*d / x = (2d)/(5x)

Tom's average speed = Tom's driving distance / Tom's driving time = (3/5)*d / x = (3d)/(5x)

To find the ratio of Peter's average speed to Tom's average speed, we can divide Peter's average speed by Tom's average speed:

(Peter's average speed) / (Tom's average speed) =   /   = (2d)/(3d) = 2/3

Therefore, the ratio of Peter's average speed to Tom's average speed is 2:3.

The answer is E. 2:3.

bumpbot · Answer

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