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Peter and Tom shared the driving on a certain trip. If Peter

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Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3
[Reveal] Spoiler: OA

Originally posted by goodglory on 04 Dec 2007, 19:07.
Last edited by Bunuel on 27 Oct 2013, 06:20, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: Peter and Tom PLEASE HELP [#permalink]

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New post 04 Dec 2007, 19:41
goodglory wrote:
Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but peter on drove 2/5 of the total distance, what was the ration of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3


welcome to gmatclub

peter speed (2d/5)/t
tom speed d/t

ratio = peter/tom = 2/5 => 2:5
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Re: Peter and Tom PLEASE HELP [#permalink]

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New post 04 Dec 2007, 22:04
goodglory wrote:
Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but peter on drove 2/5 of the total distance, what was the ration of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3


since the time take by each is equal, it is straight respective distances: 2:5
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 [#permalink]

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New post 05 Dec 2007, 11:10
The answer is suppose to be E. 2:3. It's from the GMATPrep
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 [#permalink]

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New post 05 Dec 2007, 12:00
I got E.

Peter
R1 * T = 2/5D

Tom
R2 * T = 3/5D

Using the easist LCM, 5, and easiest T, 1.



2/3
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 [#permalink]

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New post 05 Dec 2007, 12:25
goodglory wrote:
The answer is suppose to be E. 2:3. It's from the GMATPrep


This is what happens when we don't read the question correctly .
A 500 level question ..and here I am stumped...
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 [#permalink]

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New post 05 Dec 2007, 14:50
i purposely omitted the correct answer in my first post. I don't quite understand what you mean "easier LCM is 5". How would you calculate this? Where are you plugging in your numbers. It's obvious but what is the concept here? Thank you
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 [#permalink]

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New post 05 Dec 2007, 15:11
goodglory wrote:
i purposely omitted the correct answer in my first post. I don't quite understand what you mean "easier LCM is 5". How would you calculate this? Where are you plugging in your numbers. It's obvious but what is the concept here? Thank you


2/5 of the distance + 3/5 of the distance = total distance
2/5 of the distance + 3/5 of the distance = 5/5


set the total distance to 5 and the respective distances are 2 and 3.
set the total distance to 10 and the respective distances are 4 and 6
etc....
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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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New post 27 Oct 2013, 04:54
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goodglory wrote:
Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but peter on drove 2/5 of the total distance, what was the ration of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3



As time is constant for both
Distance is directly proportional to speed

pete distance = 2/5
tom distance = 3/5

Pete distance/tom distance = pete speed/tom speed
=(2/5)/(3/5)
pete speed/tom speed= 2:3
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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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New post 22 Nov 2013, 05:29
goodglory wrote:
Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Peter's average speed to Tom's average speed?

A. 1:5
B. 2:5
C. 1:2
D. 3:5
E. 2:3


If distance and time are constant then the ratio of the speeds must be 2:3

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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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New post 14 May 2014, 13:27
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Let Total Distance= 5
Peter drove= 2 mile and Tom Drove= 3 mile. Let, Each took 1 hour
Their speed = 2/1 : 3/1 = 2: 3
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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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New post 07 Feb 2015, 06:34
Let total distance be D.

Tom's covered distance is = 2D/5
Tom's rate= 2D/5T

Peter's covered distance = D-2D/5 = 3D/5
Peter's rate= 3D/5T

So Tom: Peter = 2D/5T x 5T/3D
= 2 : 3
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Re: Peter and Tom shared the driving on a certain trip. If Peter [#permalink]

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New post 15 Apr 2018, 11:30
Let
Peter's rate= r1= (2d/5)/t => 2d/5t= r
tom's rate= r2= (3d/5)/t => 3d/5t
We're asked for the ratio of their speeds
Hence:
r1/r2=(2d/5t)/(3d/5t)
r1:r2= 2:3
Re: Peter and Tom shared the driving on a certain trip. If Peter   [#permalink] 15 Apr 2018, 11:30
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Peter and Tom shared the driving on a certain trip. If Peter

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