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Bunuel

Tough and Tricky questions: Word Problems.



Q is a set of four distinct prime numbers. If the sum of the integers in Q is even and the number x is a member of Q, then what is the least value that x can be?

A. 2
B. 3
C. 4
D. 5
E. 7


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Sum of 4 prime integers is Even

So all four integers should be odd numbers as including 2 in the set will make the sum Odd

Smallest odd prime number is 3

So Ans B
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Answer = B. 3

2 + 3 + 5 + 7 = 17 (Discard as sum is ODD)

3 + 5 + 7 + 11 = 26 (Sum is even)

Least number = 3
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Bunuel

Tough and Tricky questions: Word Problems.



Q is a set of four distinct prime numbers. If the sum of the integers in Q is even and the number x is a member of Q, then what is the least value that x can be?

A. 2
B. 3
C. 4
D. 5
E. 7


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OFFICIAL SOLUTION:

(B) We are told that Q is a set of four distinct prime numbers, and the sum of the numbers in Q is even. Since the question involves odds, evens and the smallest possible prime, you should immediately think of 2, the smallest prime number and the only even prime number.

If 2 were a member of the set, then we would have one even number and three odd numbers. Since this sum would always be odd, 2 cannot be a member of the set. Thus, all the members of Q must be odd to yield an even sum.

Since all the members of the set must be odd prime numbers, the answer is the smallest odd prime number, which is 3.

Note: 1 is not a prime number.
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Isn't B the answer? shows C as the correct answer.
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Isn't B the answer? shows C as the correct answer.

Thank you for noticing. Edited.
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Bunuel

Tough and Tricky questions: Word Problems.



Q is a set of four distinct prime numbers. If the sum of the integers in Q is even and the number x is a member of Q, then what is the least value that x can be?

A. 2
B. 3
C. 4
D. 5
E. 7


Kudos for a correct solution.

Since the sum of the integers is even, we must have 4 odd prime numbers. Thus, the least value of x is 3.

Answer: B
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