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18 Aug 2019, 13:46
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45% (03:25) correct
55%
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wrong
based on 268
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Akhil must complete a project that is divided into seven subtasks by midnight on Sunday. He can only complete one subtask each day, starting Monday morning, though the subtasks can be completed in any order. The table shows each subtask as a fraction of the total work for the project. If he must complete more than half of the work for the project before Friday, is subtask S completed before Friday?
(1) Subtask R is completed on Friday and Subtask V is completed on Saturday.
(2) Subtask P is completed on Thursday and Subtask Q is completed on Monday.
Attachment:
Untitled.png [ 22.61 KiB | Viewed 7810 times ]
29 Dec 2019, 17:47
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Assume total work= LCM(3, 5, 6, 9, 15, 30, 45)= 90
P=30; Q=10; R=15; S=12; T=3; U=2; V=18
M+Tu+W+Th>90/2
Statement 1-
Fri= 15; and Sat=18
If we do't include S in first 4 days, Maximum work that can be finished in first 4 days= 30+15+2+3=45, which is not greater than 45. Hence, we must include S in first 4 days
Sufficient
Statement 2- Th=30; and M=10
If we don't include S in first 4 days, Maximum work that can be finished in first 4 days= 30+10+15+18=73>45
If we include S in first 4 days, Maximum work that can be finished in first 4 days= 30+10+18+12=70>45
Hence, both scenarios are possible.
Insufficient
Akhil must complete a project that is divided into seven subtasks by midnight on Sunday. He can only complete one subtask each day, starting Monday morning, though the subtasks can be completed in any order. The table shows each subtask as a fraction of the total work for the project. If he must complete more than half of the work for the project before Friday, is subtask S completed before Friday?
(1) Subtask R is completed on Friday and Subtask V is completed on Saturday.
(2) Subtask P is completed on Thursday and Subtask Q is completed on Monday.
P=30; Q=10; R=15; S=12; T=3; U=2; V=18
M+Tu+W+Th>90/2
Statement 1-
Fri= 15; and Sat=18
If we do't include S in first 4 days, Maximum work that can be finished in first 4 days= 30+15+2+3=45, which is not greater than 45. Hence, we must include S in first 4 days
Sufficient
Statement 2- Th=30; and M=10
If we don't include S in first 4 days, Maximum work that can be finished in first 4 days= 30+10+15+18=73>45
If we include S in first 4 days, Maximum work that can be finished in first 4 days= 30+10+18+12=70>45
Hence, both scenarios are possible.
Insufficient
wannaBEgood
Akhil must complete a project that is divided into seven subtasks by midnight on Sunday. He can only complete one subtask each day, starting Monday morning, though the subtasks can be completed in any order. The table shows each subtask as a fraction of the total work for the project. If he must complete more than half of the work for the project before Friday, is subtask S completed before Friday?
(1) Subtask R is completed on Friday and Subtask V is completed on Saturday.
(2) Subtask P is completed on Thursday and Subtask Q is completed on Monday.
Attachment:
Untitled.png
avigutman
Tutor
Joined: 17 Jul 2019
Last visit: 03 Oct 2024
Posts: 1,298
Own Kudos:
Given Kudos: 66
Location: Canada
Schools: NYU Stern (WA)
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Expert reply
06 Feb 2021, 19:52
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Video solution from Quant Reasoning starts at 16:10
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
