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since a sub task s has to be completed before Friday and work done till Friday is greater than 1/2
hence work done after friday should be less than 1/2

As per
A R+S = 1/6 +1/5 = 11/30
if s is done after friday
11/30 + 2/15 = 1/2
which means S can not be done after friday since work done should be less than half
hence sufficient

B
P and Q are task before friday and they add upto 1/3+ 1/9 = 4/9
but addition of s = 2/15 is still less than 1/2 and other task can also make upto that value greater than 1/2
Hence insifficient
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Its not hard at all, just far too long IMO
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