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The average (arithmetic mean) of two numbers is 4x. If one of the numb

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The average (arithmetic mean) of two numbers is 4x. If one of the numb [#permalink]

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New post 28 Dec 2017, 07:47
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C
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The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y
[Reveal] Spoiler: OA

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Re: The average (arithmetic mean) of two numbers is 4x. If one of the numb [#permalink]

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New post 28 Dec 2017, 08:17
Bunuel wrote:
The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y


y+b=4x*2 (since there are 2 numbers)

y+b=8x, the question says one number is y so, y+b=8x; b=8x-y
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Re: The average (arithmetic mean) of two numbers is 4x. If one of the numb [#permalink]

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New post 28 Dec 2017, 09:01
E

(a+y)/2=4x;

a+y= 8x

a=8x-y.

Hope this is fine :)



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Re: The average (arithmetic mean) of two numbers is 4x. If one of the numb [#permalink]

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New post 29 Dec 2017, 18:06
I used A to represent "the other number."

(A + y) / 2 = 4x This equation means that the average of the two numbers is equal to 4x with one of the numbers as y.

Solving the equation for A:
A + y = 8x
A = 8x - y (E is the answer).
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Re: The average (arithmetic mean) of two numbers is 4x. If one of the numb [#permalink]

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New post 31 Dec 2017, 10:27
Bunuel wrote:
The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y



An easy one.. :)

Let the other number be "N"

Thus, \(\frac{(y + N)}{2} = 4x\)

\(y + N = 8x\)

\(N = 8x - y\)

Thus, the correct answer is Option E.
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Re: The average (arithmetic mean) of two numbers is 4x. If one of the numb   [#permalink] 31 Dec 2017, 10:27
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