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Bunuel
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 28 Dec 2017, 08:47
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E
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97% (00:39) correct 3% (01:22) wrong based on 79 sessions

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The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y
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E
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 28 Dec 2017, 09:17
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Bunuel
The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y

y+b=4x*2 (since there are 2 numbers)

y+b=8x, the question says one number is y so, y+b=8x; b=8x-y
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 28 Dec 2017, 10:01
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E

(a+y)/2=4x;

a+y= 8x

a=8x-y.

Hope this is fine :)



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The average (arithmetic mean) of two numbers is 4x. If one of the numb 29 Dec 2017, 19:06
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I used A to represent "the other number."

(A + y) / 2 = 4x This equation means that the average of the two numbers is equal to 4x with one of the numbers as y.

Solving the equation for A:
A + y = 8x
A = 8x - y (E is the answer).
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 31 Dec 2017, 11:27
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Bunuel
The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y


An easy one.. :)

Let the other number be "N"

Thus, \(\frac{(y + N)}{2} = 4x\)

\(y + N = 8x\)

\(N = 8x - y\)

Thus, the correct answer is Option E.
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 29 Oct 2019, 07:33
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Bunuel
The average (arithmetic mean) of two numbers is 4x. If one of the numbers is y, then the value of the other number is

A. x - 4y
B. 4x + 4y
C. 8x - 4y
D. 4y - 8x
E. 8x - y

\(a + b = 8x\)

Now, Let \(a + y = 8x\)

So, \(a = 8x - y\), Answer must be (E)
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The average (arithmetic mean) of two numbers is 4x. If one of the numb 30 Jun 2022, 09:35
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Theory: Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\)

If the average (arithmetic mean) of two numbers is 4x and one of the numbers is y
Let other number be t
=> Sum of all the values= y + t

Using, Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\), We get
4x = \(\frac{y+t}{2}\)
=> y + t = 4x*2 = 8x
=> t = 8x-y

So, Answer will be E
Hope it helps!

To learn more about Statistics watch the following video

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