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Rabab36
Bunuel
sir can you explain this question

The average weight of 10 items is 20 kg. The weight of each item has an integral value. When the weights are arranged in descending order, the first three weights are 25 kg, 22kg and 21 kg. What can be the lowest possible weight of an item?

A. 5
B. 6
C. 7
D. 8
E. 9

The average weight of 10 items is 20 kg, so the total weight is 10*20 = 200.

We want to find the minimum weight of an item possible. To minimize the weight of that item, maximize the weight of all other items. The heaviest three boxes weigh 25 kg, 22kg and 21 kg, so we need to maximize the weight of 6 other items so that the 10th one weighs the least. The maximum weight of the mentioned six items would be 21kg. So, we'd have:

(25 + 22 + 21) + (21 + 21 + 21 + 21 + 21 + 21) + x = 200;

x = 6.

Answer: B.

14. Min/Max Problems



Hope it helps.

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