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26 Sep 2016, 06:51
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The integers v,w,x,y and z are such that 0<v<w<x<y<z. The average of these integers is 36 and median of these 5 integers is 28.
What is the greatest possible value of Z?
a) 128
b) 130
c) 140
d) 132
e) 120
Please assist with above problem..
What is the greatest possible value of Z?
a) 128
b) 130
c) 140
d) 132
e) 120
Please assist with above problem..
26 Sep 2016, 07:10
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alanforde800Maximus
The integers v,w,x,y and z are such that 0<v<w<x<y<z. The average of these integers is 36 and median of these 5 integers is 28.
What is the greatest possible value of Z?
a) 128
b) 130
c) 140
d) 132
e) 120
Please assist with above problem..
What is the greatest possible value of Z?
a) 128
b) 130
c) 140
d) 132
e) 120
Please assist with above problem..
Hi
The middle term,x, is 28 ..
Sum is average*5=36*5=180..
Since all are different let's take the min value of other 4 to get max z..
So let v be 1, w be 2, x is 28, and y be next higher 29..
So all 4 add u to 1+2+28+29=60..
So max value of z is 180-60=120..
Hope it helps
ProfX
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26 Sep 2016, 07:35
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I followed the above method. Since we need to maximize one term, we will have to minimize the other terms. Sum of the integers is 180. But since median is 28, the middle term will be 28 because there are 5 terms. Now, there will be 2 terms below 28 and 2 terms above 28. We need to minimize the sum of these 4 terms. Since they are all positive, we get 1+2+28+29= 60. Hence answer is 120
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