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Good question. The logic lies in picking up the regular hexagon principle and making it 6 equilateral triangles. Well explained Jamifahad.
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6x70x\(\sqrt{3}\)/4\([(200)^2-(50)^2]\)
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A hexagon with six equal sides can be divided up into six, equal, equilateral triangles.

We know the "base" of each triangle is 200. We also know that you can divide an equilateral triangle up into two identical 30:60:90 triangles. This allows us to find the the height of each triangle. With this we know the area (or the area of the roof) is 10000√3. Then we multiply by the height 70 to get the volume --> 700000√3. Finally, we multiply by 6 to get the total area of 4200000√3. However, we need to account for the empty space in the middle which too is an equilateral hexagon. The same process we applied to the large hexagon can be applied to the small hexagon. The base of each triangle is 50 so the height is 50√3. The area is 1/2*50*50√3 = 1250√3. Then we multiply that by the height to get volume which is 87500√3. Finally we multiply by 6 to account for the four equilateral triangles --> 525000√3. We simply subtract 525000√3 from the total to get the answer.
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madn800
6x70x\(\sqrt{3}\)/4\([(200)^2-(50)^2]\)

This is it, but I don't think this is a realistic question since the calculations needed to get to the final answer are long and tedious. The question is probably OK since it tests some basic geometry but answer choices could be somewhat summarized.

Cheers
J
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jlgdr
madn800
6x70x\(\sqrt{3}\)/4\([(200)^2-(50)^2]\)

This is it, but I don't think this is a realistic question since the calculations needed to get to the final answer are long and tedious. The question is probably OK since it tests some basic geometry but answer choices could be somewhat summarized.

Cheers
J

Actually, you don't really need to calculate a lot because we don't need to get to the actual answer. The options are such that you can find the answer by setting up the numbers. Let me explain.

The volume is given as Surface Area * Height.
What we need to do is find the surface area of the large hexagon - surface area of the small hexagon.
How do you find the area of a hexagon? Let's split in into two equal trapezoids
Area of hexagon = 2* area of trapezoid = 2*(1/2)*Height * (Sum of bases) = Height * Sum of bases

Attachment:
Ques3.jpg
Ques3.jpg [ 8.97 KiB | Viewed 4636 times ]

Since each internal angle of a hexagon is 120 degrees, we get a 30-60-90 triangle with sides in the ratio \(1:\sqrt{3}:2\). Since hypotenuse is 200, the other two sides are 100 and \(100\sqrt{3}\).

Area of large hexagon \(= 100\sqrt{3}* (200 + 400)\)
Similarly, we know that area of small hexagon \(= 25\sqrt{3}*(50 + 100)\) (instead of 200, just put 50)

Surface area of the building \(= 100\sqrt{3}* (600) - 25\sqrt{3}*(150) = 10\sqrt{3}(6000 - 375)\)
Volume will be given by multiplying the surface area by 70 (the height)

So we will have \(\sqrt{3}\) in the volume and two 0s. Only (E) satisfies these conditions.
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Ans is E
3937500√3



See attached image for more clearity.
Attachments

IMG_1188.JPG
IMG_1188.JPG [ 1.33 MiB | Viewed 3392 times ]

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