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There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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Updated on: 11 Dec 2016, 09:03
Question Stats:
73% (03:06) correct 27% (02:48) wrong based on 139 sessions
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There are 3 boxes A, B and C. In box A, there are 3 green marbles and 5 yellow marbles. In box B, there are 2 red marbles and 3 green marbles. In box C, there are 4 white marbles and 5 green marbles. Choose randomly a box then pick randomly a marble from that box. What is the probability that picked marble is green? A. 1/8 B. 55/96 C. 2/15 D. 551/1080 E. 551/360
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Originally posted by broall on 11 Dec 2016, 05:21.
Last edited by broall on 11 Dec 2016, 09:03, edited 1 time in total.



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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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11 Dec 2016, 08:55
Can you explain please?



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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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11 Dec 2016, 08:59
fleamkt wrote: Can you explain please? I'll post the solution later Why dont you try this one?
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There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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Updated on: 12 Dec 2016, 01:21
\(P(A)*P(G)+P(B)*P(G)+P(C)*P(G)\)
\(\frac{1}{3} (\frac{3}{8} + \frac{3}{5} + \frac{5}{9}) = \frac{551}{1080}\)
Answer D.
First time I got 479, have you changed something?
Thanks for posting ones again.
Originally posted by vitaliyGMAT on 11 Dec 2016, 09:37.
Last edited by vitaliyGMAT on 12 Dec 2016, 01:21, edited 2 times in total.



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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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11 Dec 2016, 09:50
vitaliyGMAT wrote: \(P(A)*P(G)+P(B)*P(G)+P(C)*P(G)\)
\(\frac{1}{3} (\frac{3}{8} + \frac{3}{5} + \frac{5}{9}) = \frac{551}{1080}\)
Answer D.
First time I got 479, have you changed something?
Thanks fo posting one again. Yes, I've corrected some typos mistakes. Sorry about that. Posted from my mobile device
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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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10 Jan 2017, 03:40
Vitality,,,,Why did u multiply by 1/3 of whole,,,please



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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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10 Jan 2017, 04:58
nguyendinhtuong wrote: There are 3 boxes A, B and C. In box A, there are 3 green marbles and 5 yellow marbles. In box B, there are 2 red marbles and 3 green marbles. In box C, there are 4 white marbles and 5 green marbles. Choose randomly a box then pick randomly a marble from that box. What is the probability that picked marble is green?
A. 1/8 B. 55/96 C. 2/15 D. 551/1080 E. 551/360 The probability of picking a green marble from the different boxes is different. Probability of picking box A = 1/3 Probability of picking a green marble from box A = 3/8 Probability of picking box B = 1/3 Probability of picking a green marble from box B = 3/5 Probability of picking box C = 1/3 Probability of picking a green marble from box C = 5/9 Probability of picking a green marble from box A, B or C = (1/3)*(3/8) + (1/3)*(3/5) + (1/3)*(5/9) = 1/8 + 1/5 + 5/27 = 551/1080
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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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13 Jan 2017, 00:13
I got the cake,,,actually I didn't observe the line,,,,choose randomly a box and then picking up marble,,,,,,Thank you Karishma mam,,,,,



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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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13 Jul 2017, 00:06
VeritasPrepKarishma wrote: nguyendinhtuong wrote: There are 3 boxes A, B and C. In box A, there are 3 green marbles and 5 yellow marbles. In box B, there are 2 red marbles and 3 green marbles. In box C, there are 4 white marbles and 5 green marbles. Choose randomly a box then pick randomly a marble from that box. What is the probability that picked marble is green?
A. 1/8 B. 55/96 C. 2/15 D. 551/1080 E. 551/360 The probability of picking a green marble from the different boxes is different. Probability of picking box A = 1/3 Probability of picking a green marble from box A = 3/8 Probability of picking box B = 1/3 Probability of picking a green marble from box B = 3/5 Probability of picking box C = 1/3 Probability of picking a green marble from box C = 5/9 Probability of picking a green marble from box A, B or C = (1/3)*(3/8) + (1/3)*(3/5) + (1/3)*(5/9) = 1/8 + 1/5 + 5/27 = 551/1080 Hello VeritasPrepKarishmaI have solved this problem in the same way. I wonder how to do this using only combinatorics. Your inputs would be great
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Re: There are 3 boxes A, B and C. In box A, there are 3 green marbles and
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