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29 Jan 2015, 08:25
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
63% (01:45) correct
37%
(01:42)
wrong
based on 676
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There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
09 Feb 2015, 07:39
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pacifist85
Bunuel
Bunuel
There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
VERITAS PREP OFFICIAL SOLUTION:
There are k boys and k girls selected (including Harvey and Jessica). Harvey can be paired with any one of the k girls. Jessica is one of the girls. The probability that Harvey will be paired with Jessica is 1/k. Notice that n has no role to play here. The required probability only needs the value of k.
Statement 1: We now know that total 5+1 = 6 boys and 6 girls were selected for the dance. So probability that Harvey will be paired with Jessica is 1/6. Sufficient.
Statement 2: This tells us that Total number of boys – k = 8. We don’t know the value of k. Not sufficient.
Answer (A)
I agree with A and the explanations.
What I would like to ask refers to the part in red. If we have 6 boys and 6 girls that will be paired together, don't we have 6*6=36 combinations of possibl pairs? So, 36 possible, different pairs? Out of these 36 pairs, Harvey and Jessica together would make one pair. So, isn't the probability 1/36?
hi pacifist,
selection of harvey is already sure as he is one of the k boys selected..
And he can be paired with any of the 6(k) girls... so it will be 1/6..
1/36 would have been correct in following scenarios..
1) there are 6 boys and 6 girls. Out of these one boy and one girl are to be choosen as a pair for dance. what is the prob of choosing harvey and jessica?
2) there are 6 boys, harvey being one of them. these 6 boys are to be paired with one of 36 girls, jessica being one of them.what is the prob of harvey being paired with jessica?
29 Jan 2015, 11:09
Kudos
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Bunuel
There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
(1) Other than Harvey, 5 boys are selected for the dance.
(2) 8 of the k boys are not selected for the dance.
Kudos for a correct solution.
ans A..
1) statement tells us k=6. sufficient
2) statement 2 not clear as k boys are selected how can 8 out of them not selected... it must be n and not k...insufficient
