I think this is a very good GMAT like 'convoluted' question. The controversy related to 1 is actually because of the confusing language the question stem uses. Let me try and put it in another way:
...and do not have a common factor with \(x\) other than 1The above statement only says that 1 is a factor of numbers less than \(x\) and not that 1 should be excluded from the set of number less than \(x\)
Lets take \(x = 7\). Below is the set of \(x\) according to question stem
6 - Less than 7, and does not have a common factor with 7 other than 1
5 - Less than 7, and does not have a common factor with 7 other than 1
4 - Less than 7, and does not have a common factor with 7 other than 1
3 - Less than 7, and does not have a common factor with 7 other than 1
2 - Less than 7, and does not have a common factor with 7 other than 1
1 - Less than 7, and does not have a common factor with 7 other than 1Hence, 1 has to be in the set!
Total elements: 6
\(x-1\)
Option
B