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505-555 (Easy)|   Algebra|            
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Bunuel
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General Discussion
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1) xy<0, it means that x and y has different signs, but not necessarily equal. NS
2) (x-y)(x+y)=0
either x=y or x=-y, as we are not certain that x+y=0, then it's NS
BOTH
as xy<0, the signs of x and y are different, then x=-y, or x+y=0 Suf
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Does x + y = 0? (OR is -x=y OR x=-y)

(1) xy<0
(2) x^2 = y^2

So
1: xy<0 so either x OR y <0 Not sufficient

2. x^2 =y^2 . |x| = |y|. But we dont know anything about the sign of either x OR y. Not sufficient

Both together
xy<0 and x^2 =y^2 : So either one of them is negative, and they have same aboslute value. Suffient to answer the question x+y=0
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Statement 1
xy < 0
x can be +ive or -ive, or can be = to y
y can be +ive or -ive, or can be = to x

With those cases in mind, inline are some samples
x=1, y=-1, will answer the question as Yes
x=2, y =-1, will answer the question as No

Statement 2
x can be +ive or -ive
y can be +ive or -ive

With those cases in mind, inline are some samples
x=1, y=-1, will answer the question as Yes
x=1, y =1, will answer the question as No

Combine both the statements and you will always get a Yes
If x is +ive, y has to be -ive
If y is +ive, x has to be -ive.

With those cases in mind, inline are some samples
x=1, y=-1, will answer the question as Yes
x=-1, y =1, will answer the question as Yes

Correct answer C.
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Bunuel
Does x + y = 0 ?

(1) xy < 0
(2) x^2 = y^2

Please correct me if I am wrong but wont the answer be E?
This is because it is not mentioned that x and y are integers. So in case of both the statements combined, the value of x and y could be a decimal for eg., 0.1 which would satisfy both the conditions, but x+y wont be equal to zero
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mmshake
Bunuel
Does x + y = 0 ?

(1) xy < 0
(2) x^2 = y^2

Please correct me if I am wrong but wont the answer be E?
This is because it is not mentioned that x and y are integers. So in case of both the statements combined, the value of x and y could be a decimal for eg., 0.1 which would satisfy both the conditions, but x+y wont be equal to zero

Think about it, if x = 0.1, what would be the value of y, and what would be the value of x + y?
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Bunuel
mmshake
Bunuel
Does x + y = 0 ?

(1) xy < 0
(2) x^2 = y^2

Please correct me if I am wrong but wont the answer be E?
This is because it is not mentioned that x and y are integers. So in case of both the statements combined, the value of x and y could be a decimal for eg., 0.1 which would satisfy both the conditions, but x+y wont be equal to zero

Oh right! Got it now! Thank you so much! :blushing: :blushing:
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Does x + y = 0 ?

(1) xy < 0
(2) x^2 = y^2

Statement 1:
either x<0 or y<0.
x may or may not equal to -y.

Statement 2:
(x+y)(x-y) = 0
x = -y or x = y
thus x+y may or may not equal to 0

Combing the two statements, x = -y. thus x+y = 0

hence C
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