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05 Sep 2015, 12:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (02:13) correct
45%
(02:22)
wrong
based on 82
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A saltwater solution completely fills a glass cylinder. If the solution is then poured into a larger rectangular aquarium, what percent more solution would be needed to completely fill the aquarium?
(1) The ratio of the diagonal of the base of the aquarium to the diameter of the cylinder is 1: sq rt 2
(2) The height and width of the aquarium are equal to the height and diameter of the cylinder.
(1) The ratio of the diagonal of the base of the aquarium to the diameter of the cylinder is 1: sq rt 2
(2) The height and width of the aquarium are equal to the height and diameter of the cylinder.
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05 Sep 2015, 15:28
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Yash12345
A saltwater solution completely fills a glass cylinder. If the solution is then poured into a larger rectangular aquarium, what percent more solution would be needed to completely fill the aquarium?
For these type of problems I normally try and visualize and think if the statements allow for variance in the objects volume. Important to note is that they are asking for the percentage of volume difference, which you can think of a ratio in the volume of one to another.
(1) The ratio of the diagonal of the base of the aquarium to the diameter of the cylinder is 1: sq rt 2... Before you get bogged down and put pen to paper, just think of the huge variance in size this allows for the rectangular tank. Just assign some arbitrary value "a" to the diameter of the cylinder which will equal some other value "b" you could end up having a base that is a square, which maximizes the area of the base or a base that is almost as long as "b", which will bring the area close to 0. clearly INSUFF
(2) The height and width of the aquarium are equal to the height and diameter of the cylinder... Once again, you don't even need to put pen to paper here, This will allow you to fit the cylinder into the tank however gives no information about the length, meaning it could be a completely maximized fit or the tank might be any number of meters longer in excess of the cylinder... Clearly INSUFF
(1) & (2)... (2) will lock in the height and the width, and (1) will lock in the length by controlling the size of the diagonal SUFFICIENT
Answer: C
Apologies for the wordy answer, and hope it's clear. I ALWAYS make mistakes in the execution of math problems when there is algebra with a lot of moving parts so whenever possible I try and solve the problems visually with logic... This is often a helpful in DS problems which don't require you to actually "calculate" anything.
31 Mar 2018, 01:06
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Bunuel
There seems to be a flaw in this question.
As per statement 1,
Diagonal of Aquarium / Diameter of cylinder =1: sq rt 2
As per Statement 2,
Width of Aquarium = Diameter of cylinder
Hence Combining, we get
Diagonal of Aquarium / Width of Aquarium =1: sq rt 2
Which is not possible because the diagonal of base = hypotenuse of right triangle which is formed by length & width.
Hence diagonal is always greater than width/length, Hence wording of question is not correct.
There seems to be a flaw in this question.
As per statement 1,
Diagonal of Aquarium / Diameter of cylinder =1: sq rt 2
As per Statement 2,
Width of Aquarium = Diameter of cylinder
Hence Combining, we get
Diagonal of Aquarium / Width of Aquarium =1: sq rt 2
Which is not possible because the diagonal of base = hypotenuse of right triangle which is formed by length & width.
Hence diagonal is always greater than width/length, Hence wording of question is not correct.
Yash12345
