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505-555 (Easy)|   Algebra|                     
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Video solution from Quant Reasoning:
General Discussion
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generis
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sashiim20
AbdurRakib
Attachment:
2018.OG.05.072.q.png
A. \(\frac{1}{3}\)
B. \(\frac{4}{3}\)
C. 3
D. 4
E. 12

\(\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = r(\frac{1}{9}+\frac{1}{12}+\frac{1}{15}+\frac{1}{18})\)

\(\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = r*\frac{1}{3}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6})\)

\(r*\frac{1}{3} =0\)

\(r = 3.\) Answer (C)..


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Please Press "+1 Kudos" to appreciate. :-D

sashiim20 - Nice! But I think you have a typo.

\(\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = r*\frac{1}{3}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6})\) - if you divide LHS by last factor on RHS, I think you get 1.

So in highlighted part, \(r*\frac{1}{3} =0\), I think RHS should be 1, not 0. Otherwise you'll get

\(r*\frac{1}{3} * 3 =0 * 3\)

\(r = 0\)
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Silly typo mistake. Thank you ... Updated the post. :)
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12
Attachment:
2018.OG.05.072.q.png

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\)

Or, \(\frac{20+15+12+10}{60} = \frac{r(20+15+12+10)}{180}\)

Or, \(20+15+12+10 = \frac{r(20+15+12+10)}{3}\)

Or, \(57*3 = r*57\)

So, \(r = 3\)

Thus, answer will be (C)
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12

We can simplify the given expression by multiplying by 180 and we have:

60 + 45 + 36 + 30 = 20r + 15r + 12r + 10r

171 = 57r

r = 3

Alternate Solution:

We should note that each fraction on the left hand side is 3 times the corresponding fraction on the right.

For instance 1/3 is 3 times 1/9, 1/4 is 3 times 1/12, etc.

Thus, r MUST be 3.

Answer: C
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why cannot we multiply the right side simply by 3 but 1/3?
Sorry, cannot understand this moment...
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12

Attachment:
2018.OG.05.072.q.png



\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\)

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{3*3} + \frac{1}{3*4} + \frac{1}{3*5} + \frac{1}{3*6})\)

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = \frac{r}{3}(\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6})\)

\(1=\frac{r}{3}\)

\(r=3\)

C is the Correct answer
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12


Attachment:
2018.OG.05.072.q.png

To solve this question, we need to recognize that there's a 1/3 + 1/4 + 1/5 + 1/6 "hiding" in 1/9 + 1/12 + 1/15 + 1/18
We can reveal this "secret" by factoring 1/3 out of 1/9 + 1/12 + 1/15 + 1/18
We get: 1/9 + 1/12 + 1/15 + 1/18 = (1/3)(1/3 + 1/4 + 1/5 + 1/6)

So.....
Given: 1/3 + 1/4 + 1/5 + 1/6 = r(1/9 + 1/12 + 1/15 + 1/18)
Factor right side to get: 1/3 + 1/4 + 1/5 + 1/6 = (r)(1/3)(1/3 + 1/4 + 1/5 + 1/6)
Divide (1/3 + 1/4 + 1/5 + 1/6) from both sides to get: 1 = (r)(1/3)
Multiply both sides by 3 to get: 3 = r
Answer:
RELATED VIDEO

I kept looking what is that I cannot see. I could not spot it. I solved it manually in 2 minutes and got the right answer and then I was able to see. Hahaha!
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take 1/3 common from the equation after =
cross multiply.
R=3

This has to be the fastest way
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12

Attachment:
2018.OG.05.072.q.png

Given: \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\)

Asked: r = ?

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = 3(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\)

r = 3

IMO C
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Let (1/3 + 1/4 + 1/5 + 1/6) = A
Take 1/3 common from the right hand side.
Then, we have:

A = r*1/3* A
so, r = 3

Ans. C

One may also commit a silly mistake and choose A. - write this in error log. Don't ignore
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12

Attachment:
2018.OG.05.072.q.png

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\)

\((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r\frac{1}{3}(\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6})\)

\(1=\frac{1}{3}r\)

\(r=3\)

The answer is \(C\)
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Solution:

1/3+1/4+1/5+1/6=r(1/9+1/12+1/15+1/18)

=>1/3+1/4+1/5+1/6=r∗1/3(1/3+1/4+1/5+1/6) (Taking the 1/3 common)

=>r∗1/3=1

=>r=3.r=3 (option c)

Devmitra Sen (GMAT Quant Expert)
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AbdurRakib
If \((\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}) = r(\frac{1}{9} + \frac{1}{12} + \frac{1}{15} + \frac{1}{18})\), then r =

A. \(\frac{1}{3}\)

B. \(\frac{4}{3}\)

C. 3

D. 4

E. 12

Attachment:
2018.OG.05.072.q.png



Answer: Option C

Video solution by GMATinsight

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Given, (1/3+1/4+1/5+1/6)=r(1/9+1/12+1/15+1/18)

=> (1/3+1/4+1/5+1/6)=r(1/9+1/12+1/15+1/18)
=> (1/3+1/4+1/5+1/6)=r/3(1/3+1/4+1/5+1/6)
=> 1=r/3
=> r =3

Hence C
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