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MathRevolution
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 04:08
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[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
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C
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 04:14
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more

How can option A.121 fit the question criteria? IMO both A and C are answers

Posted from my mobile device
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 04:26
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[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)

How can option A.121 fit the question criteria? IMO both A and C are answers

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Assume x = 0 and y = 11; then x^2 + y ^2 = 0 + 121 = 121 i.e. Option A

Hence only Option C remains as an answer.
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 04:29
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)

How can option A.121 fit the question criteria? IMO both A and C are answers

Posted from my mobile device

Assume x = 0 and y = 11; then x^2 + y ^2 = 0 + 121 = 121 i.e. Option A

Hence only Option C remains as an answer.
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Got it. Thanks. Kudos to you

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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 04:34
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Got it. Thanks. Kudos to you

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Thank you so much!!!
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 06:47
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more


the one point you require to know is that \(11^2=121\)..
\(A. 121... 0^2+11^2\)
\(B. 122... 1^2+11^2\)
\(C. 123... ??? \) you require to check if \(10^2, \ \ 9^2 \ \ or \ \ 8^2\) can be added to any other square to get 123 .. NO
\(D. 125.. 2^2+11^2\)
\(E. 130... 3^2+11^2\)

C
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If x and y are integers, which of the following CANNOT be the value of 25 Jan 2018, 10:32
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more

Let's do this systematically:
0² = 0
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
10² = 100
11² = 121

A. 121 = 0² + 11² ELIMINATE A
B. 122 = 1² + 11² ELIMINATE B
C. 123 = can't eliminate
D. 125 = 10² + 5² ELIMINATE D
E. 130 = 9² + 7² ELIMINATE E

Answer: C

Cheers,
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If x and y are integers, which of the following CANNOT be the value of 26 Jan 2018, 22:43
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more

This can be easily solved by taking one of the Integer as 11.
Hence, C.
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If x and y are integers, which of the following CANNOT be the value of 28 Jan 2018, 18:45
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=>

Squares of even integers, \((2k)^2 = 4k^2\) have the remainder \(0\), when they are divided by \(4\).

Squares of odd integers, \((2k+1)^2 = 4k^2 + 4k + 1\) have the remainder \(1\), when they are divided by \(4\).

Hence, squares of integers can have remainders of \(0\) or \(1\) only, when they are divided by \(4\). So, the sum of two squares of integers cannot have the remainder of \(3\) when it is divided by \(4\).

Thus, \(123\) cannot be the value of \(x^2+y^2\).
Therefore, the answer is C.
Answer: C
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If x and y are integers, which of the following CANNOT be the value of 29 Jan 2018, 10:34
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more

Let’s test our answer choices:

A) 121

121 = 0^2 + 11^2

B) 122

122 = 1^1 + 11^2

C) 123

There are no two perfect squares that sum to 123.

Answer: C
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If x and y are integers, which of the following CANNOT be the value of 24 Jun 2022, 22:12
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MathRevolution
[GMAT math practice question]

If \(x\) and \(y\) are integers, which of the following CANNOT be the value of \(x^2+y^2\)?

\(A. 121\)
\(B. 122\)
\(C. 123\)
\(D. 125\)
\(E. 130\)
Show more

As the highest number is 130, we can start to check with 11square (12 square is 144).

11ˆ2= 121, 121+9=130, Option E eliminate,
121+ 4= 125, Option D eliminate,
121+1= 122, Option B eliminate,
121+0= 121, Option A eliminate.

Option C is left. hence, answer is C
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If x and y are integers, which of the following CANNOT be the value of 17 Jan 2024, 22:14
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