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Train A and Train B began traveling towards each other from opposite

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Joined: 02 Sep 2009
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Train A and Train B began traveling towards each other from opposite  [#permalink]

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21 Feb 2016, 12:58
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15% (low)

Question Stats:

84% (01:41) correct 16% (02:00) wrong based on 251 sessions

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Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

Kudos for correct solution.

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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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21 Feb 2016, 19:33
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Distance = 500 mile
Speed of train A = 35 miles per hour
Speed of train B = 25 miles per hour
Relative speed of both trains
= 35+ 25
=60 miles per hour
Time = Distance / Speed
= 500/60
=8 hours and 20 mins

Since the trains started at 1 PM , they will meet at 9:20 PM

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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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21 Feb 2016, 20:43
2
Bunuel wrote:
Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

Kudos for correct solution.

This question tests your concepts of relative speed:
If two trains are moving in opposite direction, then distance will reduce at a rate of (Speed of 1 + Speed of 2)
If two trains are moving in same direction, then distance will reduce at a rate of (Speed of 1 - Speed of 2)

Here the trains are moving towards each other, hence in opposite direction.
Trains will cover the 500 mile track in a time of 500/(25 + 35) = 500/60 = 8 hours and 20 minutes.

Trains started at 1:00 PM, there they will meet at 9:20 PM
Option E
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Joined: 24 Aug 2016
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Train A and Train B began traveling towards each other from opposite  [#permalink]

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12 Sep 2016, 22:54
1
Suppose trains meet at x distance from the start. Train A have to cover x Miles and train B have to cover 500-x = Miles.

Lets assume trains meet after time t hours.

distance = Speed * Time.

For train A: x = 35 * t
For train B: 500-x = 25 * t ==> ( Substitute value of x from above) 500- ( 35 * t ) = 25 * t ==> 500 = 60 t ==> t = 8$$\frac{2}{6}$$ => 8 hours 20 minutes.

Ansswer --> E
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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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18 Mar 2017, 20:42
Lets say that the Trains will meet each other after Time T.
Therefore, Dist Traveled by A + Distance Traveled by B = 500 m.
35T + 25T = 500m.
T = 8.3 Hours.
Trains will meet @ 01:00pm + 08:30 Hrs = 09:20 PM

Narayana raju
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Joined: 08 Sep 2016
Posts: 32
Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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08 Jun 2017, 22:24
How did u get 8.20..isnt it 8.30?

Please explain..i seem to have truble following Time-Distance questions.

Skywalker18 wrote:
Distance = 500 mile
Speed of train A = 35 miles per hour
Speed of train B = 25 miles per hour
Relative speed of both trains
= 35+ 25
=60 miles per hour
Time = Distance / Speed
= 500/60
=8 hours and 20 mins

Since the trains started at 1 PM , they will meet at 9:20 PM

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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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09 Jun 2017, 10:19
Imo E
They are traveling in opposite direction then relative speed is 60
Total distance to be covered is 500 miles
Thus hours 500/60 8 hours and 20 min

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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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09 Jun 2017, 10:46
Attachment:

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Ans : E
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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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13 Jun 2017, 11:16
2
Bunuel wrote:
Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

We are given that Trains A and B traveled toward each other at 1 p.m. and that Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour. We are also given that they started 500 miles apart.

We can let the time of each train = t hours. Thus, the distance of Train A is 35t and the distance of Train B is 25t.

Let’s create the following equation to determine t:

distance of Train A + distance of Train B = total distance

35t + 25t = 500

60t = 500

t = 500/60 = 50/6 = 25/3 = 8 ⅓ hours = 8 hours and 20 minutes.

Thus, the trains met at 1 p.m. + 8 hours and 20 minutes = 9:20 p.m.

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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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13 Aug 2017, 12:45
Bunuel wrote:
Train A and Train B began traveling towards each other from opposite ends of a 500-mile long track at 1:00 PM. If Train A traveled at 35 miles per hour and Train B traveled at 25 miles per hour, at what time did the trains meet?

A. 5:40 PM
B. 6:00 PM
C. 7:20 PM
D. 8:00 PM
E. 9:20 PM

Kudos for correct solution.

So one thing we can notice about this question- is that the answer can't be an integer because if both trains start at the same time then how can we multiply the rates by an integer time and have the same distance when one is greater than the other? For example 35 x some integer cannot equal 25 times the same integer. Secondly, this question requires us to make an approximation so it is an approximation and opposite ends question and the formula for opposite ends is

Distance 1 + Distance 2 = Total Distnce

Distance A =35 (t) - we assume they start at the same time unless told oetherwise

Distance B= 25(t)

35(t) +25(t) =500
60t= 500
500/60= 8.33333

so this should be

E
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Re: Train A and Train B began traveling towards each other from opposite  [#permalink]

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10 Oct 2018, 08:03
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Re: Train A and Train B began traveling towards each other from opposite   [#permalink] 10 Oct 2018, 08:03
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