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30 Jun 2016, 07:45
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68% (02:16) correct
32%
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Two trains are traveling on a collision course. If train A is traveling at a speed of 350 mph and train B is traveling 28% slower, how much time will it take the trains to collide if the initial distance between the two is 1505 miles?
A. Two hours and 30 minutes.
B. One hour and 10 minutes.
C. Two hours and 25 minutes.
D. Three hours and 15 minutes.
E. Four hours and 20 minutes.
A. Two hours and 30 minutes.
B. One hour and 10 minutes.
C. Two hours and 25 minutes.
D. Three hours and 15 minutes.
E. Four hours and 20 minutes.
Senthil1981
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30 Jun 2016, 09:12
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Answer is A. Two hours and 30 minutes.
Since they are racing towards each other, the speed is accumulative, ie. 350 mph + 350*0.72 = 602 (0.72 because the second train is 28% slower)
So time before collision is total distance / total speed = 1505/602 = 2.5 hours or 2 hours and 30 mins
Since they are racing towards each other, the speed is accumulative, ie. 350 mph + 350*0.72 = 602 (0.72 because the second train is 28% slower)
So time before collision is total distance / total speed = 1505/602 = 2.5 hours or 2 hours and 30 mins
Updated on: 30 Jun 2016, 10:23
Originally posted by CounterSniper on 30 Jun 2016, 10:08.
Last edited by CounterSniper on 30 Jun 2016, 10:23, edited 1 time in total.
Last edited by CounterSniper on 30 Jun 2016, 10:23, edited 1 time in total.
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let S1 and S2 be the speeds of train A and B
S1 is 350 and S2=28% less = 252
time taken = S1+S2/1505
which is
1505/602 =x
where 2<x<3
therefore C !!
S1 is 350 and S2=28% less = 252
time taken = S1+S2/1505
which is
1505/602 =x
where 2<x<3
therefore C !!
