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Hadrienlbb
A manager hired 4 employees to complete a certain project in 15 days. After 10 days of work the employees completed only half of the project. How many additional employees should the manager hire to finish this project in time if each employee works at the same constant rate?

A) 1
B) 2
C) 3
D) 4
E) 5


Let the total work be 60 emp-days and the rate of each employee be 1 emp-days/day.
After 10 days, only half of the work is completed. Therefore, remaining work= (1/2)*60 emp-days= 30 emp-days.
To complete the remaining work in 5 days, we need (30 emp-days/5 days) = 6 employees.
Hence, the manager needs to hire 2 additional employees to complete the work in the stipulated time.

Answer should be B.

Hope this helps.

Cheers.
You are taking a wrong assumption. The manager hired 4 employees to complete a work in 15 days. This doesn't necessarily mean that the work is of (15*4) units.

Using your approach, in 10 days 4 employees can complete 40 units of work. Therefore, remaining would be 40 units, since in 10 days only half the work was completed.
40 units can be completed in 5 days by (40/5) = 8 employeess.

Therefore, additional 8-4=4 employees must be included. Hence, answer is D.

Cheers,
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Hadrienlbb
A manager hired 4 employees to complete a certain project in 15 days. After 10 days of work the employees completed only half of the project. How many additional employees should the manager hire to finish this project in time if each employee works at the same constant rate?

A) 1
B) 2
C) 3
D) 4
E) 5

4 workers have completed the first half of the project in 10 days
in half that time, 5 days, twice as many workers will complete the second half
4
D
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4 Employees completed half work in 10 days so rate of each employee is equal to
10 days*4(Rate of one employee)= 1/2, Rate of one employee = 1/80, given we have to complete 1/2 work in 5 days with each employee working at 1/80 rate , lets calculate how many employees required in total
5 days* x employees(1/80)=1/2.............. solving this we get x=8 so total 8 employees would be require to complete work we already have 4 hired so new requirement is 4 additional employees
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Hadrienlbb
A manager hired 4 employees to complete a certain project in 15 days. After 10 days of work the employees completed only half of the project. How many additional employees should the manager hire to finish this project in time if each employee works at the same constant rate?

A) 1
B) 2
C) 3
D) 4
E) 5


Hi..

Just another way

How many mandays was expected 4*15=60
What has already been spent 4*10=40 to do half work so actual mandays required = 40*2=80...
So remaining work has to be done in 60-40 =20, which otherwise would get over in 80-40=40, double of 20 days..
So ofcourse you require double the person to complete the work, otherwise being done in double the time... So double the manpower =2*4=8
Extra manpower requirement =8-4=4
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Hadrienlbb
A manager hired 4 employees to complete a certain project in 15 days. After 10 days of work the employees completed only half of the project. How many additional employees should the manager hire to finish this project in time if each employee works at the same constant rate?

A) 1
B) 2
C) 3
D) 4
E) 5

The rate for the 4 employees is (1/2)/10 = 1/20.

We see that that the rest of the job has to be completed in 5 days, so the rate must be (1/2)/5 = 1/10.

Since 4 employees have a rate of 1/20, 8 employees would have a rate of 1/10, so 4 more employees must be hired.

Answer: D
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Reword the question:

4 employees complete half the project in 10 days. How many additional employees are needed to complete the project in 15 days?

* 4 employees completed half in 10 days
* How do we complete the second half of the project in half the amount of time? We need to double the number of employees.

Therefore, we need another 4 employees. Answer is D.
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They completed half the job in 10 days that is 1/30, and the remaining needs to be done in 1/2 the time. Hence they need double the force, at current pace. Current pace is 4 employees and they would need 8 in total, hence answer is 4
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