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If n is an integer, is n even?

(1) 2n is an even integer.
(2) n – 1 is an odd integer

Solution:
Given n is an integer.

Statement 1:
Case 1: n=3. We get 2n=6. So we get a "No" Scenario.
Case 2: n=4. We get 2n=8. So we get a "Yes" Scenario.
Therefore, this statement is insufficient.

Statement 2:

If n-1= Odd, We get n= Odd+1,i.e n= Odd+Odd=Even.
Therefore this statement is sufficient.

The answer is Option B.
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Bunuel
If n is an integer, is n even?

(1) 2n is an even integer.
(2) n – 1 is an odd integer

(1) n could be even or odd for 2n to be even..not sufficient

(2) n-1 is an odd integer means n is even

Answer B
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If n is an integer, is n even?

(1) 2n is an even integer

2 Multiplied by any integer (EVEN or ODD) will be even

Hence, from this we cannot say if n is EVEN or ODD

Hence, (1) =====> is NOT SUFFICIENT

(2) n – 1 is an odd integer

\(n - 1 = ODD\)

This is only possible if n is EVEN

Hence, (2) =====> is SUFFICIENT

Hence, Answer is B
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I understand the rules mentioned other posts regarding rules of adding subtracting multiplying and dividing integers, for example odd.odd = even eg 2.2=4 or even - odd = odd eg 2-1=1 ....and so on and so forth, but in this question when you plug in numbers it doesn't make sense to me.

In Statement 1, 2n is an even integer, I agree it is not sufficient

if we let n=1 (odd) then we have 2.1=2 (even)
or n=2 (even) then we have 2.2 = 4 (even) .....so n can be an odd or even number....therefore statement 1 is not sufficient

In statement 2 is the following possible?
n – 1 is an odd integer

let n=2 (even) : 2-1= 1 (odd) so far so good....

however if we let
n=1 (odd) : 1-1 = 0 (even). Can we not count the number zero as an even integer in this question? therefore statement 2 also not sufficient?? also how about n= -1 or n= -3 ??

1+2 together
2n is an even integer.
n – 1 is an odd integer

2(n-1) can be odd or even??...therefore not sufficient either!.......Hense why I opted for Answer E
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