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Asad
In the \(xy\)-coordinate plane shown below, if \(xy≠0\), then the point (\(x,y\)) lies in which quadrant?
1) point (\(x-y, x+y\)) lies in the second quadrant.
2) \(xy<0\)

1) In the second quadrant point (x,y) is like, x<0 and y>0. So, x -y < 0 and x +y > 0. When x=-5, y = 6, this condition is true. Again when, x = 2, y = 4, it is true. In the first case(x,y) is in the second quadrant and in the second case (x,y) in the first quadrant. Not sufficient.
2) x and y has opposite signs. So they can either lie in the second and fourth quadrant. Not sufficient.
Together,(x,y) can situate only in second quadrant.Sufficient.
C is the answer.
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