
In the figure shown, quadrilateral ABCD is inscribed in a circle of radius 5. What is the perimeter of quadrilateral ABCD?
(1) The length of AB is 6 and the length of CD is 8......>no information about the lengths of other two sides(information required because we don't know which specific quadrilateral is quadrilateral ABCD above),
Insufficient(2) AC is a diameter of the circle.........>So now we know AC=10 and its opposite angle \(\angle\)ABC=\(90^{\circ}\)(for \(\triangle\) ABC) and \(\angle\)ADC=\(90^{\circ}\)(for \(\triangle\) ADC),But still we don know the lengths of any sides of the Quadrilateral ABCD,
Insufficient(1)+(2) AB=6,AC=10 and \(\angle\)ABC=\(90^{\circ}\) so According to pythagorean triple BC=\(\sqrt{AC^2+AB^2}\)=\(\sqrt{10^2-6^2}\)=8
Accordingly we can find AD=6
So,perimeter of quadrilateral ABCD=AB+BC+CD+AD=6+8+8+6=28,
SufficientCorrect Answer C