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MathRevolution
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1. Angle is 120°, however we would need the radius and something to find the area of triangle. So this statement is insufficient.
2. Length of the chord is given here, however this statement alone is insufficient.

Combining both we would get the radius and subsequently the area of triangle.

So answer should be C

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My take is E
It has to be explicitly mentioned that O is the center of the circle !!!!!!
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MathRevolution
Attachment:
5.8.png

What is the area of the region AOB shaded shown as above?

1) \(∠AOB=120^o\)
2) \(AB=50\)

Solution
Statement 1: not sufficient, as we can not find anything from this.
Statement 2: AB= 50 can not help us to find anything
Statement 1+2: radius of the circle can be found using formula lengh(AB)=2(pi)r*angle/360. As triangle ABC forms isosceles triangle.... its height can be found out, and hence Area of ABC can be determined.
Ans is C :thumbup:
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Area of an Isosceles triangle:

A=b/4(sqrt(4*a^2-b^2)

b---base
a--equal side

Combining we get both and b
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ShivamoggaGaganhs
Area of an Isosceles triangle:

A=b/4(sqrt(4*a^2-b^2)

b---base
a--equal side

Combining we get both and b



The way you wrote the formula is hard to understand. What does sqrt mean?
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Hi chetan2u, Bunuel, VeritasKarishma,

Could one of you experts please explain why option B is insufficient? Isnt there a rule that's something along the lines of the angle opposite is the diameter of the circle? So in our case angle 0= 90 degree and AB would be the diameter? Or can we not assume that AB is a diameter as it could be a chord merely?
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JS1290
Hi chetan2u, Bunuel, VeritasKarishma,

Could one of you experts please explain why option B is insufficient? Isnt there a rule that's something along the lines of the angle opposite is the diameter of the circle? So in our case angle 0= 90 degree and AB would be the diameter? Or can we not assume that AB is a diameter as it could be a chord merely?

AB is NOT a diameter. A diameter of a circle goes through the center. AB in the figure does not go through O.
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Not sure whether such question types are tested but one needs to know the below prop

1. the perpendicular from the center to any chord (line that connects any 2 points on the circle) will be a perpendicular bisector.


Once you know that you can drop a perpendicular bisector and then the big triangle gets divided into 2 smaller 30-60-90 triangle.

C
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Bunuel, Can you please explain how C is sufficient? Statement (2) gives AB = 50, is this the length of the arc AB or chord AB. If it is the chord AB, I do not understand how C is sufficient.

Thanks in advance.
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Bunuel, Can you please explain how C is sufficient? Statement (2) gives AB = 50, is this the length of the arc AB or chord AB. If it is the chord AB, I do not understand how C is sufficient.

Thanks in advance.


The rule is side length opposite the angles as

30 - S
60 - S×(root 3)
90 - 2S

You know that the chord will bisect

So side opposite angle 60 is 25..
Rest you can solve once you get S

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