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08 Nov 2018, 09:45
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77% (00:40) correct
23%
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What is the area of the triangle above?
(1) \(a^2\)+ 9 = 25
(2) x = 90 degrees
Attachment:
DS1.jpg [ 3.62 KiB | Viewed 5495 times ]
08 Nov 2018, 10:09
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What is the area of the triangle above?
(1) \(a^2\)+ 9 = 25
(2) x = 90 deg
Attachment:
DS1.jpg
(1) \(a^2\)+ 9 = 25 ==> a=4 ==> Now the three sides are 3,4,5 - a pythagorian triplet. Hence X=90 deg. Thus area = \(\frac{1}{2} * 3 *4\) - Sufficient
(2) x = 90 deg ==> area = \(\frac{1}{2} * 3 *a\) ........and \(a^2\) = 5^2 -3^2 ==> a=4 ==>Hence, area =\(\frac{1}{2} * 3 *4\) - Sufficient
Ans D.
08 Nov 2018, 10:37
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From statement 1 we can solve for a to get value as 4
As a^2=25-9=16
Area of triangle =0.5*b*h
=0.5*4*3=6
Sufficient
From statement 2 using pythagorean triplet we can get a=4 and get the area of triangle as in statement 1 above. sufficient
D should be the correct choice.
Sent from my Redmi Note 3 using GMAT Club Forum mobile app
As a^2=25-9=16
Area of triangle =0.5*b*h
=0.5*4*3=6
Sufficient
From statement 2 using pythagorean triplet we can get a=4 and get the area of triangle as in statement 1 above. sufficient
D should be the correct choice.
Sent from my Redmi Note 3 using GMAT Club Forum mobile app
