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17 Jan 2020, 00:02
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What is the greatest possible area of a triangular region with one side that corresponds with the diameter of a circle with radius 6, and the other vertex of the triangle on the circle?
(A) 24
(B) 36
(C) 40
(D) 48
(E) 72
Updated on: 22 Jan 2020, 09:34
Originally posted by freedom128 on 17 Jan 2020, 02:47.
Last edited by freedom128 on 22 Jan 2020, 09:34, edited 4 times in total.
Last edited by freedom128 on 22 Jan 2020, 09:34, edited 4 times in total.
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One side of a triangle has length of 12 (diameter of a circle). This side will be the base.
The maximum height of the triangle is 6 (radius of a circle)
Maximum area=0.5*12*6=36
FINAL ANSWER IS (B)
The maximum height of the triangle is 6 (radius of a circle)
Maximum area=0.5*12*6=36
FINAL ANSWER IS (B)
General Discussion
17 Jan 2020, 01:56
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What is the greatest possible area of a triangular region with one side that corresponds with the diameter of a circle with radius 6, and the other vertex of the triangle on the circle?
(A) 24
(B) 36
(C) 40
(D) 48
(E) 72
Isosceles triangle will have max area in the circle, with radius = 6 and diameter = 12,
So, 45-45-90 - x:x:x√2, here x√2 = 12, so x= 6√2.
Area of the triangle = 1/2*6√2*6√2 = 36
Ans. B
(A) 24
(B) 36
(C) 40
(D) 48
(E) 72
Isosceles triangle will have max area in the circle, with radius = 6 and diameter = 12,
So, 45-45-90 - x:x:x√2, here x√2 = 12, so x= 6√2.
Area of the triangle = 1/2*6√2*6√2 = 36
Ans. B
