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Re: What is the lowest positive integer that is divisible by each of the i [#permalink]
divisible by
1,2,3,4,5,6,7,8
LCM = 2^3*7*5*3
=840
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What is the lowest positive integer that is divisible by each of the i [#permalink]
I simply applied divisibility rules from 2 to exclude numbers that do not qualify. Since all the numbers end with 0, it was very easy and quick to apply most of the divisibility rules:

420, 560, 840, 960, 1080

Divisibility by 2: all qualify
Divisibility by 3: 420, 560 out
Divisibility by 4, 5 & 6: all remaining qualify
Divisibility by 7: 84 is divisible by 7, 96 & 108 no

Answer: C

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Re: What is the lowest positive integer that is divisible by each of the i [#permalink]
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Lowest positive integer that is is divisible by integers 1 through 8
= (2^3)x3x5x7 = 840
Answer 'C'
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Re: What is the lowest positive integer that is divisible by each of the i [#permalink]
Integers are 1,2,3,4,5,6,7,8..
The Lowest Positive Integer among the answer Choice is 420.
Applied Divisibility Rule to 420.
420 is divisible by 1,2,3,4,5,6,7 except 8.
Multiplying 420 by 2 = 420 *2 = 840 ... Answer C....

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Re: What is the lowest positive integer that is divisible by each of the i [#permalink]
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Re: What is the lowest positive integer that is divisible by each of the i [#permalink]
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