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10 Dec 2018, 03:08
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What is the perimeter of a rhombus?
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
10 Dec 2018, 05:40
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Bunuel
What is the perimeter of a rhombus?
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
diagnoal of rhombus bisect at 90* and adjacents sides are equal so if we know diagonal length we can find perimeter
from 1
area of rhombus : 0.5 * d1*d2
d1*d2= 280
d1 and d2 not know
in sufficient
from 2
d1 = 48
so two sides would be
2x^2= 48
x^2=24
x= 2 sqrt6
we dont know other two sides so in sufficient
from 1 & 2
d2* 48= 280
d1= 5.8 ~ 6
so other two sides
2x^2= 6
x^2= 3
x= sqrt 3 = ~1.7 = ~ 2
so perimeter = 2 * ( 2+ 2 sqrt6 )= 2* ~7 = 14
IMO C
07 Mar 2019, 05:49
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Archit3110
Bunuel
What is the perimeter of a rhombus?
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
(1) Its area is 140 square meters
(2) One of its diagonals is 48 meters
diagnoal of rhombus bisect at 90* and adjacents sides are equal so if we know diagonal length we can find perimeter
from 1
area of rhombus : 0.5 * d1*d2
d1*d2= 280
d1 and d2 not know
in sufficient
from 2
d1 = 48
so two sides would be
2x^2= 48
x^2=24
x= 2 sqrt6
we dont know other two sides so in sufficient
from 1 & 2
d2* 48= 280
d1= 5.8 ~ 6
so other two sides
2x^2= 6
x^2= 3
x= sqrt 3 = ~1.7 = ~ 2
so perimeter = 2 * ( 2+ 2 sqrt6 )= 2* ~7 = 14
IMO C
Hi Archit3110,
Thank you for your solution But I am unable to get the following part,May be I am missing something,
Archit3110
d1 = 48
so two sides would be
2x^2= 48
x^2=24
x= 2 sqrt6
How do we know that the two adjacent sides form a 90 Deg. angle to use Pythagoras theorem. I assume you meant to write \(2x^2= 48^2\), where x is one side of a rhombus. Also if we knew X, shouldn't we know all the sides of the rhombus as in a Rhombus all the sides are equal.
Thank you.
