Bunuel
What is the remainder when the positive integer x is divided by 31?
(1) When x + 10 is divided by 31 the remainder is zero.
(2) When x + 33 is divided by 10 the remainder is zero.
We use the “quotient remainder theorem,” which states: dividend = quotient x divisor + remainder.
We need to determine the remainder when the positive integer x is divided by 31. That is, if we express x as 31Q + R for some nonnegative integers Q and R where R < 31, then R is the remainder when x is divided by 31.
Statement One Alone:
When x + 10 is divided by 31, the remainder is zero.
Thus:
(x + 10)/31 = Q + 0/31
(x + 10)/31 = Q
x + 10 = 31Q
x = 31Q - 10
x = 31Q - 31 + 31 - 10
x = 31(Q - 1) + 21
Since Q - 1 is an integer and since 21 < 31, we see that when x is divided by 31, the remainder is 21.
Statement one alone is sufficient to answer the question.
Statement Two Alone:
When x + 33 is divided by 10, the remainder is zero.
Thus:
(x + 33)/10 = Q + 0/31
(x + 33)/10 = Q
x + 33 = 10Q
x = 10Q - 33
We see that if Q = 4, then x = 7 and the remainder when x is divided by 31 is 7. However, if Q = 5, then x = 17 and the remainder when x is divided by 31 is 17. Statement two is not sufficient to answer the question.
Answer: A