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When 15n where n is a positive integer, is divided by 6, the remainder
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Bunuel
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When 15n where n is a positive integer, is divided by 6, the remainder [#permalink] New post  12 Nov 2017, 22:40
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When 15n, where n is a positive integer, is divided by 6, the remainder is x. What is the value of x?

(1) When n is divided by 2, the remainder is 0.

(2) When n is divided by 3, the remainder is 0.
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Re: When 15n where n is a positive integer, is divided by 6, the remainder [#permalink] New post  12 Nov 2017, 22:51
A

From st1 we can know that n is a positive even number.
ie2,4,6,8...
So 15n/6 will always give the remainder 0. Sufficient

From st2 n is a multiple of 3. For odd multiples of 3 the remainder of 15n/6 is 3. But for even multiple of 3 it’s 0. Two values. So insufficient


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Re: When 15n where n is a positive integer, is divided by 6, the remainder [#permalink] New post  12 Nov 2017, 23:44
Since 15n=3*5*n and has 3 as a factor, we just need to figure out whether n is a multiple of 2 or not
(1) Sufficient, now we know that n is divisible by 2, so the remainder when 15n is divided by 6 is zero
(2) This information gives us no new inferences, because 15n has 3 as a factor itself

Answer A.
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Re: When 15n where n is a positive integer, is divided by 6, the remainder [#permalink] New post  13 Oct 2019, 11:02
Bunuel wrote:
When 15n, where n is a positive integer, is divided by 6, the remainder is x. What is the value of x?

(1) When n is divided by 2, the remainder is 0.

(2) When n is divided by 3, the remainder is 0.




Hi everyone,

we can write the question statement as follows: 15n= 6q +x

Now: 5*3n=3*2q + x ---> 5n=2q + x

The question now is "is n divided by 2? and if not what's n?"

Statement 1 clearly tells us that n is divisible by 2. Hence sufficient.

statement 2 tells us that n is divisible by 3 but we don't know whether it is also divisible by 2. Hence not sufficient

Option A
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