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When a person aged 39 is added to a group of n people, the average age

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When a person aged 39 is added to a group of n people, the average age [#permalink]

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When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of n?

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11

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[Reveal] Spoiler: OA

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Re: When a person aged 39 is added to a group of n people, the average age [#permalink]

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New post 19 Aug 2015, 01:34
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Answer according to me: A

Let's assume that the total no. of people is n and the initial average is x.

So we can assume that the total sum of ages would be nx initially.

When the guy aged 39 is added to the total, the new sum of ages would be (nx+39). The new average now would be (nx+39)/n+1. We already know that now the average(x) is increased by 2. so we can equate the two above saying:

(nx+39)/(n+1) = x+2
solving this equation:
nx+39=(x+2)(n+1)
nx+39=nx +x +2n+2


we get,

2n+x=37

When the guy aged 15 is added to the total, the new sum of ages would be (nx+15). The new average now would be (nx+15)/n+1. We already know that now the average(x) is decreased by 1. so we can equate the two above saying:

(nx+15)/(n+1) = x-1

we get

x-n=16

solving the two equation simultaneously, we get n's value as 7.

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Re: When a person aged 39 is added to a group of n people, the average age [#permalink]

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Bunuel wrote:
When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of n?

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11

Ans: A

Solution: lets say avg is x so total is (xn):
now with the first condition
(nx+39)/n+1 = x+2
2n+x = 37 Eq.1

with second condition
(nx+15)/n+1 = x-1
x-n = 16 Eq.2

by solving Eq1 and Eq2 we can find out n=7
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When a person aged 39 is added to a group of n people, the average age [#permalink]

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When a person aged 39 is added to a group of n people, the average age increases by 2.
(Sum+39)/(n+1) = avg+2

When a person aged 15 is added instead, the average age decreases by 1.
(Sum+15)/(n+1) = avg-1

We can take the 1st equation and subtract from the 2nd equation to isolate n.
24=3n+3
n=7

Answer:


(A) 7

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Re: When a person aged 39 is added to a group of n people, the average age [#permalink]

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New post 19 Aug 2015, 11:56
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A simple and elegant solution.

As addition of 39, shifts mean by 2, and addition of 15, shifts mean by 1 to the other side, we have the mean lying between 39 & 15, and in a ratio of 2:1

39-15 = 24
24 divide by 3 is 8.

Meaning mean of the n terms is 15+8 = 39-16 = 23

Now, from first statement, When a person aged 39 is added to a group of n people, the average age increases by 2.

n*23 +39 = 25*(n+1)

n = 7

Ans. (A)

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Re: When a person aged 39 is added to a group of n people, the average age [#permalink]

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New post 23 Aug 2015, 11:58
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Bunuel wrote:
When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of n?

(A) 7
(B) 8
(C) 9
(D) 10
(E) 11

Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION:

What is the first thing you can say about the initial average? It must have been between 39 and 15. When a person aged 39 is added to the group, the average increases and when a person aged 15 is added, the average decreases.

Let’s look at the second case first. When the person aged 15 is added to the group, the average becomes (initial average – 1). If instead, the person aged 39 were added to the group, there would be 39 – 15 = 24 extra which would make the average = (initial average + 2). This difference of 24 creates a difference of 3 in the average. This means there must have been 24/3 = 8 people (after adding the extra person). The value of n must be 8 – 1 = 7.
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When a person aged 39 is added to a group of n people, the average age [#permalink]

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Here is my solution to this one -->
Let the original Mean = \(p\)
Thus original sum = \(p*n\)
Where \(n\) is the number of people in the original set.
we need to get

As per question =>
\(\frac{p*n+39}{n+1} = p+2\)
\(p+2n=37\)-> Equation 1

Also
\(\frac{p*n+15}{n+1} = p-1\)

Hence \(p-n=16\)--> Equation 2

Hence using the two equations (1 and 2)
\(n=7\)


Hence A
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Re: When a person aged 39 is added to a group of n people, the average age [#permalink]

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New post 09 Dec 2016, 03:14
One more method -->

Let Mean=p
APQ=> 2(n+1)=39-p
Hence p+2n=37

Also -1(n+1)=15-p
Hence p=16+n
Clearly Both of these Equations are as the above method.



To know Everything about Mean or Statistics in general, refer to this Post -->
statistics-made-easy-all-in-one-topic-203966.html#p1563151

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Re: When a person aged 39 is added to a group of n people, the average age   [#permalink] 28 Dec 2017, 10:07
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