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Bunuel
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Afc0892
2\(x^2\) − 20x = 48 can be reduced to \(x^2\)-10x-24 = 0.

\(x^2\)-12x+2x-24 = 0

x(x-12) + 2(x-12) = 0

Either x = 12 or x = -2.

E is the answer.

Hello Afc0892 !

Is it possible to solve it by Viete's theorem?

-b/a?
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we can quickly put the value of root in equation and see which one satisfy this


12 is correct.

Posted from my mobile device
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Bunuel
Which of the following is a root of the equation 2x^2 − 20x = 48?

A. -4
B. 2
C. 6
D. 8
E. 12

Dividing the equation by 2, we have:

x^2 - 10x = 24

x^2 - 10x - 24 = 0

(x - 12)(x + 2) = 0

x = 12 or x = -2

Answer: E
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I found another way (2x+4)(x-12) => yields same answer...
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