From question stem
Working together at their respective rates, machine A, B, and C can finish a certain work in 8/3 hours.
Working alone, if A took A hours, B took B hours and C took C hours to complete the work, in an hour A will complete \(\frac{1}{A}\) of the work, B will complete \(\frac{1}{B}\) of the work and C will complete \(\frac{1}{C}\) of the work.
So, A, B, and C working together will, in an hour, complete \(\frac{1}{A} + \frac{1}{B} + \frac{1}{C}\) of the work ... (1)
If the machines together take \(\frac{8}{3}\) hours to complete the work, they will complete \(\frac{3}{8}\) of the work in an hour .... (2)
Equating (1) and (2), we get \(\frac{1}{A} + \frac{1}{B} + \frac{1}{C} = \frac{3}{8}\) ... (3).
Statement 1: Working together, A and B can finish the work in 4 hours.
i.e., \(\frac{1}{A} + \frac{1}{B} = \frac{1}{4}\) ... (4)
Solving (3) and (4) will give us a unique value for C. But we will not get a unique value for A.
Statement 1 alone is NOT sufficient. Eliminate options A and D.
Statement 2: Working together, B and C can finish the work in 48/7 hours.
i.e., i.e., \(\frac{1}{B} + \frac{1}{C} = \frac{7}{48}\) ... (5)
Solving (3) and (5) will give us a unique value for A.
Statement 2 alone is sufficient.
Choice B is the answer.