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A and B have 7 and 8 common. So one of them has to be the number common to all three sets.

1. 7 is not in C -> leaves us with 8, SUFFicient

2. 8 is in C -> confirm that it's 8, SUFFicient


Hence D.

In (1), what if C contains just one number of 9?
In (2), what if C contains 8 and 7?
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ritwikkg
A and B have 7 and 8 common. So one of them has to be the number common to all three sets.

1. 7 is not in C -> leaves us with 8, SUFFicient

2. 8 is in C -> confirm that it's 8, SUFFicient


Hence D.

In (1), what if C contains just one number of 9?
In (2), what if C contains 8 and 7?

whoops! got it now, thanks!
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zhanbo ritwikkg
Sorry but as part of statement 1, how is C going to contain 9? 9 isn't present in either of the sets A and B. And the stimulus states that x is a number common in all three sets so x could be either 7/8/both 7 and 8.
Since statement 1 says that 7 is not there in the set C, it must be 8. It cannot be 0/1/2 since those numbers are not present in sets A and B and thus we would be violating the condition of the stimulus. IMO answer will be A.
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zhanbo ritwikkg
Sorry but as part of statement 1, how is C going to contain 9? 9 isn't present in either of the sets A and B. And the stimulus states that x is a number common in all three sets so x could be either 7/8/both 7 and 8.
Since statement 1 says that 7 is not there in the set C, it must be 8. It cannot be 0/1/2 since those numbers are not present in sets A and B and thus we would be violating the condition of the stimulus. IMO answer will be A.

We are only told: Set C is another set.

It can contain anything from none (an empty set) to a single number of 9 to everything in the universe including you and me.
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zhanbo ritwikkg
Sorry but as part of statement 1, how is C going to contain 9? 9 isn't present in either of the sets A and B. And the stimulus states that x is a number common in all three sets so x could be either 7/8/both 7 and 8.
Since statement 1 says that 7 is not there in the set C, it must be 8. It cannot be 0/1/2 since those numbers are not present in sets A and B and thus we would be violating the condition of the stimulus. IMO answer will be A.

We are only told: Set C is another set.

It can contain anything from none (an empty set) to a single number of 9 to everything in the universe including you and me.

You are right, C is an another set,but it cannot be an empty set since we are told that x is common across all three sets.So if it was an empty set, it would not have any common factor, but it also has to have a common factor. And the only two common factors, it can have are 7 and 8

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zhanbo
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zhanbo ritwikkg
Sorry but as part of statement 1, how is C going to contain 9? 9 isn't present in either of the sets A and B. And the stimulus states that x is a number common in all three sets so x could be either 7/8/both 7 and 8.
Since statement 1 says that 7 is not there in the set C, it must be 8. It cannot be 0/1/2 since those numbers are not present in sets A and B and thus we would be violating the condition of the stimulus. IMO answer will be A.

We are only told: Set C is another set.

It can contain anything from none (an empty set) to a single number of 9 to everything in the universe including you and me.

You are right, C is an another set,but it cannot be an empty set since we are told that x is common across all three sets.So if it was an empty set, it would not have any common factor, but it also has to have a common factor. And the only two common factors, it can have are 7 and 8

Posted from my mobile device

You are right.

I misread the sentence. I though x represents the number of common elements across all three sets.

Kudos to you!
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