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A circle with center (1, 0) and radius 2 lies in the coordinate plane

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A circle with center (1, 0) and radius 2 lies in the coordinate plane  [#permalink]

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New post 17 Sep 2018, 22:15
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  55% (hard)

Question Stats:

48% (01:03) correct 52% (01:39) wrong based on 24 sessions

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A circle with center (1, 0) and radius 2 lies in the coordinate plane shown above. If point (x, y) lies on the circle is (x, y) in quadrant 3?

(1) |y| > 1
(2) |x| > 1

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Re: A circle with center (1, 0) and radius 2 lies in the coordinate plane  [#permalink]

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New post 18 Sep 2018, 01:59
Bunuel wrote:
Image
A circle with center (1, 0) and radius 2 lies in the coordinate plane shown above. If point (x, y) lies on the circle is (x, y) in quadrant 3?

(1) |y| > 1
(2) |x| > 1


circle with centre (1, 0) and radius 2 will have equation as \((x-1)^2 + (y-0)^2 = 2^2\)


(1) |y| > 1
i.e. y > 1 or y < -1
@x=0, y=+√3
nothing about x hence
NOT SUFFICIENT

(2) |x| > 1
i.e. x > 1 or x < -1
x<-1 can't on the circle hence x >1 is the only possibility and then the point can NOT be in 3rd Quadrant hence
SUFFICIENT

Answer: Option B
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Re: A circle with center (1, 0) and radius 2 lies in the coordinate plane &nbs [#permalink] 18 Sep 2018, 01:59
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