GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Jun 2018, 08:42

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A company that ships boxes to a total of 12 distribution

Author Message
Intern
Joined: 25 May 2008
Posts: 41
A company that ships boxes to a total of 12 distribution [#permalink]

### Show Tags

16 Oct 2008, 13:45
00:00

Difficulty:

(N/A)

Question Stats:

100% (03:30) correct 0% (00:00) wrong based on 15 sessions

### HideShow timer Statistics

A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding?(Assume that the order of the colors in a pair does not matter)

a. 4
b. 5
c. 6
d. 12
e. 24.

I am assuming this question is to do with permutations and combinations.
Could someone please tell me the answer, and also explain how to solve this kind of question... I got dead confused

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Manager
Joined: 14 Oct 2008
Posts: 158

### Show Tags

16 Oct 2008, 14:30
I did not use any particular permutation or com formula.
Consider 2 colours, you can distinguish 3 centers on the basis of that, 1 for each colour and 1 for them together
Similarly, with 3 colours - 3 + 3 = 6 centers.
With 4 colours - 4 single + 3+2+1 = 10 centers
so it has to be 5 colours.
Manager
Joined: 15 Apr 2008
Posts: 159

### Show Tags

16 Oct 2008, 17:25
yes, 5 colors

4 individual colors + 4C2=10 centers
since we need to cover 12 centers we need one more color, so with 5 colors we can cover all 12 centers

what is the OA
Current Student
Joined: 28 Dec 2004
Posts: 3293
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

16 Oct 2008, 19:23
I get 5 as well

5 + 5C2 will be enough ...

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: PS: Distribution Centres   [#permalink] 16 Oct 2008, 19:23
Display posts from previous: Sort by