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08 Feb 2017, 01:34
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D
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A rectangular label with an area of 18 square inches. is wrapped around a can that is 3 inches tall, such that the label exactly covers the outside of the can excluding the top and the bottom. What is the volume of the can, in cubic inches?
A. 27π
B. 27
C. 18
D. 27/π
E. 18/π
A. 27π
B. 27
C. 18
D. 27/π
E. 18/π
08 Feb 2017, 07:34
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Height of the can = width of the label = 3
Area of rectangular label = 18 = 3 * 6. --> Circumference = 2*pi*r = 6
r = 3/pi
Volume of the can = \(pi*r^2*h\) = 27/pi
Answer: D
Area of rectangular label = 18 = 3 * 6. --> Circumference = 2*pi*r = 6
r = 3/pi
Volume of the can = \(pi*r^2*h\) = 27/pi
Answer: D
08 Feb 2017, 18:42
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curved surface area of cylinder: 2*Pi*r*h=18(area of rectangle).. Here h=3(given height of can)
2*pi*r*3=18 => r = 3/pi
Volume of can(cylinder)=Pi*\(r^2\)*h
=> pi*\((3/Pi)^2\)*3
=27/pi
So answer is D
2*pi*r*3=18 => r = 3/pi
Volume of can(cylinder)=Pi*\(r^2\)*h
=> pi*\((3/Pi)^2\)*3
=27/pi
So answer is D
