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T+S = 400 => 10% is teachers => T = 40

400 new people => total_T+total_S = 800.

5% teachers => (5/100)x800 = 40 => No new teachers should be part of the 400 people.

Therefore, Option E = 0
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Bunuel
A school is comprised of 400 people both teachers and students. If 10 percent of the people are teachers and 400 new people enter the school in the following year, how many of those people must be teachers in order to decrease the percentage of teachers to 5 percent?

A. 50
B. 35
C. 25
D. 10
E. 0

We are given that there are 400 total teachers and students, and that 10% of the people are teachers. Thus, there are 0.1 x 400 = 40 teachers. We are also given that 400 people enter the school, and we need to determine how many of those people must be teachers to decrease the percentage of teachers to 5 percent. We can let t = the number of new teachers and create the following equation:

teachers/total = 5%

(40 + t)/(400 + 400) = 1/20

(40 + t)/800 = 1/20

20(40 + t) = 800

800 + t = 800

t = 0

Alternate Solution:

We currently have a group of 400 individuals, 10% of whom are teachers. We will add 400 additional individuals, whose percentage (p) is unknown. This will result in our having 800 individuals, 5% of whom are teachers. We can summarize this in the following equation:

400(0.10) + 400p = 800(0.05)

40 + 400p = 40

400p = 0

p = 0

The percentage of teachers in the new group is 0%, which means that none of the people in the new group will be teachers.

Answer: E
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