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# A survey of potential voters was conducted to determine the likelihood

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Intern
Joined: 18 Nov 2013
Posts: 41
A survey of potential voters was conducted to determine the likelihood  [#permalink]

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15 Sep 2018, 00:11
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Difficulty:

15% (low)

Question Stats:

87% (01:56) correct 13% (02:13) wrong based on 46 sessions

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A survey of potential voters was conducted to determine the likelihood that ordinance A would be passed. 40 percent of those surveyed indicated they were not likely to vote, while the remainder indicated that they were likely to vote. Of those who indicated they were likely to vote, 35 percent indicated that they supported ordinance A, 25 percent indicated that they were undecided, and the remainder indicated that they did not support ordinance A. What percentage of potential voters are likely to vote against ordinance A?

18%
20%
24%
30%
36%
Math Expert
Joined: 02 Aug 2009
Posts: 7684
Re: A survey of potential voters was conducted to determine the likelihood  [#permalink]

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15 Sep 2018, 04:58
harish1986 wrote:
A survey of potential voters was conducted to determine the likelihood that ordinance A would be passed. 40 percent of those surveyed indicated they were not likely to vote, while the remainder indicated that they were likely to vote. Of those who indicated they were likely to vote, 35 percent indicated that they supported ordinance A, 25 percent indicated that they were undecided, and the remainder indicated that they did not support ordinance A. What percentage of potential voters are likely to vote against ordinance A?

18%
20%
24%
30%
36%

Let the number of potential voters be 100..
Person not likely to vote =40%=40, so person likely to vote = 100-40=60
% who would not support ordinance A = (100-35-25)%=40%
So in number = 40% of 60 =60*40/100=24

24 as % of 100 is 100*24/100=24%

C
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Re: A survey of potential voters was conducted to determine the likelihood  [#permalink]

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12 Feb 2019, 20:42
harish1986 wrote:
A survey of potential voters was conducted to determine the likelihood that ordinance A would be passed. 40 percent of those surveyed indicated they were not likely to vote, while the remainder indicated that they were likely to vote. Of those who indicated they were likely to vote, 35 percent indicated that they supported ordinance A, 25 percent indicated that they were undecided, and the remainder indicated that they did not support ordinance A. What percentage of potential voters are likely to vote against ordinance A?

18%
20%
24%
30%
36%

We can let n = the total number of voters.

Thus, 0.6n are likely to vote.

Since 100 - 35 - 25 = 40 percent of likely voters said they will vote against ordinance A, 0.4(0.6n) = 0.24n voters will vote against it.

So 0.24n/n = 0.24 = 24% of the potential voters are likely to vote against it.

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Re: A survey of potential voters was conducted to determine the likelihood   [#permalink] 12 Feb 2019, 20:42
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