GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 06 Dec 2019, 11:05

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Aaron will jog from home at x miles per hour and then walk back home

Author Message
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 59587
Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

16 Jul 2012, 04:46
11
107
00:00

Difficulty:

35% (medium)

Question Stats:

77% (02:20) correct 23% (02:46) wrong based on 2063 sessions

HideShow timer Statistics

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) $$\frac{xt}{y}$$

(B) $$\frac{(x+t)}{xy}$$

(C) $$\frac{xyt}{(x+y)}$$

(D) $$\frac{(x+y+t)}{xy}$$

(E) $$\frac{(y+t)}{x}-\frac{t}{y}$$

Diagnostic Test
Question: 24
Page: 23
Difficulty: 650

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 59587
Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

20 Jul 2012, 03:54
24
17
SOLUTION

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.
_________________
Director
Joined: 22 Mar 2011
Posts: 584
WE: Science (Education)
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

Updated on: 20 Jul 2012, 08:58
29
6
Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

Diagnostic Test
Question: 24
Page: 23
Difficulty: 650

GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

The correct answer should have units of length (distance).
Also, we cannot add/subtract velocities and time, it has no meaning. Therefore, we can immediately eliminate answers B, D and E.
The expression in A has units of time, so it cannot be the correct answer.
Only C is left, and it is the correct answer. It also has the correct units of length.

Formally, if we denote by D the distance we are looking for, we can write the equation:
D/x + D/y = t, from which, solving for D we get D =xyt/(x+y).
(time spent jogging + time spent walking = total time)

Note: The answer should not depend on whether Aaron first jogs and then walks, or the other way around. This means that the expression for the distance should be symmetrical in x and y (meaning, it doesn't change if we switch between x and y). The only expressions on the list of answers which fulfill this condition are C and D. But D has velocities added to time, therefore it cannot be correct.
This is just another way to easily pinpoint the correct answer.
_________________
PhD in Applied Mathematics
Love GMAT Quant questions and running.

Originally posted by EvaJager on 16 Jul 2012, 11:07.
Last edited by EvaJager on 20 Jul 2012, 08:58, edited 1 time in total.
General Discussion
Director
Joined: 22 Mar 2011
Posts: 584
WE: Science (Education)
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

20 Jul 2012, 07:57
6
Bunuel wrote:
SOLUTION

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

This is a question for which an algebraic approach would be much faster than number picking.
When working with numbers, one easily forgets about units and meanings, and for example, we have no problem in adding speeds to time. Such operations have no meaning in the real, physical world. Once you see x + t or y + t, don't even bother to check that answer.

So, don't be afraid of letters and a little algebra. And first of all, think of the meaning!!!
_________________
PhD in Applied Mathematics
Love GMAT Quant questions and running.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9850
Location: Pune, India
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

20 Jul 2012, 21:33
15
12
[quote="Bunuel"]The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

A note here:

When one travels at speed x for time t and at a speed y for time t (same amount of time), the average speed for the journey is (x+y)/2 i.e. arithmetic mean of x and y.
This is because average speed = Total Distance/Total time = (xt + yt)/2t = (x + y)/2

When one travels at speed x for distance d and at a speed y for distance d (same distance), the average speed for the journey is 2xy/(x+y)
This is so because average speed = Total Distance/Total time = 2d/(d/x + d/y) = 2xy/(x + y)

You don't really need to learn these formulas but knowing that there are these special cases will increase your speed. Once you use them a couple of times, you will automatically remember these.

In this question, if you know that average speed will be 2xy/(x+y), you multiply it by t to get total distance traveled which is 2xyt/(x+y). So distance one way must be xyt/(x+y)
_________________
Karishma
Veritas Prep GMAT Instructor

Manager
Joined: 12 Jan 2013
Posts: 142
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

17 Dec 2013, 10:20
1
Bunuel wrote:
SOLUTION

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

Hi, I do not understand how you did this step:

$$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$

How do you go from the leftward equation to the right? Can you explain in more detail? Thanks in advance.
Math Expert
Joined: 02 Sep 2009
Posts: 59587
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

18 Dec 2013, 01:54
4
2
aeglorre wrote:
Bunuel wrote:
SOLUTION

Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

Hi, I do not understand how you did this step:

$$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$

How do you go from the leftward equation to the right? Can you explain in more detail? Thanks in advance.

$$d(\frac{1}{x}+\frac{1}{y})=t$$;

$$d(\frac{y+x}{xy})=t$$;

$$d=\frac{xyt}{x+y}$$.

Hope it's clear.
_________________
Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2809
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

20 Jul 2017, 16:39
5
1
Bunuel wrote:
Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) xt/y
(B) (x+t)/xy
(C) xyt/(x+y)
(D) (x+y+t)/xy
(E) (y+t)/x-t/y

We can let d = the distance traveled when walking and jogging.

Thus, the jogging time is d/x and the walking time is d/y. Since the total time is t:

d/x + d/y = t

Multiply the entire equation by xy:

dy + dx = txy

d(y + x) = txy

d = txy/(y + x)

_________________

Jeffrey Miller

Jeff@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Manager
Joined: 07 Jun 2017
Posts: 160
Location: India
Concentration: Technology, General Management
GMAT 1: 660 Q46 V38
GPA: 3.6
WE: Information Technology (Computer Software)
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

12 Sep 2017, 04:42
1
Always Average is equal to total distance by total time.
In this case
(D/x+D/Y) = t
Hence
D = xyt/(x+y)
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 4125
Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

Updated on: 01 Dec 2019, 19:21
Top Contributor
Bunuel wrote:
Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) $$\frac{xt}{y}$$

(B) $$\frac{(x+t)}{xy}$$

(C) $$\frac{xyt}{(x+y)}$$

(D) $$\frac{(x+y+t)}{xy}$$

(E) $$\frac{(y+t)}{x}-\frac{t}{y}$$

Let d = the number of miles (distance) that Aaron JOGS.
This also means that d = the distance that Aaron WALKS.

total time = (time spent jogging) + (time spent walking)
In other words: t = (time spent jogging) + (time spent walking)
Since time = distance/speed, we can write: t = d/x + d/y [our goal is to solve this equation for d]
The least common multiple of x and y is xy, so we can eliminate the fractions by multiplying both sides by xy. When we do so, we get...
txy = dy + dx
Factor right side to get: txy = d(x + y)
Divide both sides by (x+y) to get: txy/(x+y) = d

So, the correct answer is C

Cheers,
Brent
_________________
Test confidently with gmatprepnow.com

Originally posted by GMATPrepNow on 28 Apr 2018, 08:31.
Last edited by GMATPrepNow on 01 Dec 2019, 19:21, edited 1 time in total.
VP
Joined: 09 Mar 2016
Posts: 1229
Re: Aaron will jog from home at x miles per hour and then walk  [#permalink]

Show Tags

04 Jul 2018, 05:44
Bunuel wrote:
I'm lost with this question too. Can someone please explain? thanks!

Aaron will jog home at x miles per hour and then walk back home on the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?
A. xt/y
B. (x+t)/xy
C. xyt/(x+y)
D. (x+y+t)/xy
E. (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

Hello Bunuel can you please rephrase the question "How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?"

I simply could not understand what this question want ? Total distance done by walking and jogging ?

thanks
Math Expert
Joined: 02 Sep 2009
Posts: 59587
Re: Aaron will jog from home at x miles per hour and then walk  [#permalink]

Show Tags

04 Jul 2018, 11:28
1
dave13 wrote:
Bunuel wrote:
I'm lost with this question too. Can someone please explain? thanks!

Aaron will jog home at x miles per hour and then walk back home on the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?
A. xt/y
B. (x+t)/xy
C. xyt/(x+y)
D. (x+y+t)/xy
E. (y+t)/x-t/y

Algebraic approach:

Say the distance Aaron jogs is $$d$$ miles, notice that the distance Aaron walks back will also be $$d$$ miles (since he walks back home on the same route).

Next, total time $$t$$ would be equal to the time he spends on jogging plus the time he spends on walking: $$\frac{d}{x}+\frac{d}{y}=t$$ --> $$d(\frac{1}{x}+\frac{1}{y})=t$$ --> $$d=\frac{xyt}{x+y}$$.

Number picking approach:

Say the distance in 10 miles, $$x=10$$ mile/hour and $$y=5$$ mile/hour (pick x and y so that they will be factors of 10).

So, Aaron spends on jogging 10/10=1 hour and on walking 10/5=2 hours, so total time $$t=1+2=3$$ hours.

Now, we have that $$x=10$$, $$y=5$$ and $$t=3$$. Plug these values into the answer choices to see which gives 10 miles. Only answer choice C fits: $$\frac{xyt}{x+y}=\frac{10*5*3}{10+5}=10$$.

Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

Hello Bunuel can you please rephrase the question "How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?"

I simply could not understand what this question want ? Total distance done by walking and jogging ?

thanks

Say the distance in d miles. Aaron jogs d miles at x mile/hour and then walks back the same d miles at y mile/hour. So, Aaron spends on jogging d/x hours and on walking d/y hours, so total time (from home jogging and back walking) takes him t = d/x + d/y hours.

Now, the question asks to find the distance (d) Aaron jogs (How many miles from home can Aaron jog). So, basically the question asks to express d in terms of x, y, and t.

Hope it's clear.
_________________
VP
Joined: 23 Feb 2015
Posts: 1338
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

16 Apr 2019, 03:54
2
Bunuel wrote:
Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?

(A) $$\frac{xt}{y}$$

(B) $$\frac{(x+t)}{xy}$$

(C) $$\frac{xyt}{(x+y)}$$

(D) $$\frac{(x+y+t)}{xy}$$

(E) $$\frac{(y+t)}{x}-\frac{t}{y}$$

This question is excerpted from Official Guide 2017 edition
Question# PS Diagnostic test 24

When can we ADD or SUBTRACT things in the real world?
------> ONLY when BOTH have EXACTLY THE SAME UNITS.

REMEMBER:
NEVER pick an answer choice that's absurd in the real world!

From the question,
x,y=SPEEDS in MILES/HOUR
t=TIME in HOUR
Considering only Numerator part:
B) $$x+t$$ ----> $$\frac{miles}{hour}+hour$$
We're mistakenly adding TIME with SPEED. So, out.

D) $$x+y+t$$ -----> $$\frac{miles}{hour}+\frac{miles}{hour}+hour$$
Again, we can't add TIME with SPEED. So, bye.

E) $$y+t$$ ------> $$\frac{miles}{hour}+hour$$
Again, we're mistakenly adding 2 DIFFERENT units! So, out.

We're eliminating B,D, and, E because they don't make sense in real life.

Now, considering both Denominator and Numerator:
A) $$\frac{xt}{y}$$ -----> $$\frac{miles}{hour}/\frac{miles}{hour} × hour$$
---> hour (this is NOT our goal; our goal is MILES). So, out.

C) $$\frac{xyt}{x+y}$$ ------> Considering "denominator"
------> Considering Denominator: equation (1)
x+y ----> $$\frac{miles}{hour}$$ + $$\frac{miles}{hour}$$ gives the unit $$\frac{miles}{hour}$$

------> Considering Numerator: equation (2)
xyt ----> $$\frac{miles}{hour}$$ × $$\frac{miles}{hour}$$ × hour

Dividing equation (2) by equation (1): We get miles
---> This is our goal.
_________________
“The heights by great men reached and kept were not attained in sudden flight but, they while their companions slept, they were toiling upwards in the night.”

SEARCH FOR ALL TAGS
Manager
Joined: 24 Dec 2011
Posts: 55
Location: India
GPA: 4
WE: General Management (Health Care)
Re: Aaron will jog from home at x miles per hour and then walk back home  [#permalink]

Show Tags

10 Jun 2019, 05:27
lets consider the distance is d.

so time taken (t1) for jogging is d/x
time taken (t2) for walking is d/y

Given that the t1+t2=t

t=(d/x)+(d/y)
d=t* (xy)/(x+y)
Non-Human User
Joined: 09 Sep 2013
Posts: 13721
Re: Aaron will jog from home at x miles per hour  [#permalink]

Show Tags

23 Sep 2019, 05:23
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Aaron will jog from home at x miles per hour   [#permalink] 23 Sep 2019, 05:23
Display posts from previous: Sort by