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Bunuel
Did it take a certain ship less than 3 hours to travel 9 kilometers? (1 kilometer = 1,000 meters)

(1) The ship's average speed over the 9 kilometers was greater than 55 meters per minute.
(2) The ship's average speed over the 9 kilometers was less than 60 meters per minute.

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1) stat 1 tells us that the avg speed was >55 m per min..
so in 3 hours it would travel>55*3*60 or 9900...
so the ship took less than 3 hrs to travel 9 kms... suff

2) stat 2 tells us that the avg speed was <60 m per min..
so in 3 hours it would travel<60*3*60 or 10800...
so the ship could have travelled <>=9 kms... insuff

ans A
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Rephrasing the question in terms of speed since the options A and B are given in average speed.

Traveling 9 KMs in less than 3 hours means speed should be greater than (s=d/t) s> 9/3 or 3 KM/Hour or 3000 Meters/60 Mins or
50 meters/mins . So, we can rephrase the question as Is average speed is greater than 50 Meters/Min ?

(A) Sufficient

(B) Insufficient. Speed can be 10 meters/min, 50 meters/min or 59 meters/min (All are less than 60 meters/min)

Answer: A
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Formula : Dist = Speed * Time
If Dist is constant & Speed Increases -> Time will decrease
If Dist is constant & Speed Decreases -> Time will Increase

Using statement 1: Speed Min ~ 55m/min, Dist = 9000m
Time Max = Dist/Speed Min = 9000/55 = 163mins < 3 Hrs [If speed > 55, time will decrease further]
Therefore sufficient!

Using statement 2: Speed Max ~ 60m/min, Dist = 9000m
Time Min = Dist/Speed Max = 9000/60 = 150mins [If speed decreases, time will increase further & may even exceed 3 hrs ]
Therefore Insufficient!

Hence A !!
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Hi All,

A similarly-themed question can be found in the Diagnostic Test of the OG13/GMAT2015/GMAT2016:

if-paula-drove-the-distance-from-her-home-to-her-college-at-135196.html

GMAT assassins aren't born, they're made,
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Speed = Distance / Time
And Avg Speed = Total Distance/Total Time
St 1 - Avg speed = more than 55meter/min = 55/1000 x 1/60(min) = 3.3km/h
9/3.3 < 3 for sure
Suff
St 2 - Avg speed = less than 60meter/min = lets say 20/1000x1/60 = 1.2km/h
9/1.2 > 3
also lets take Avg speed = 59meter/min = 9 / (59/1000 x 1/60) < 3

Thus NS

Answer A
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Bunuel
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Did it take a certain ship less than 3 hours to travel 9 kilometers? (1 kilometer = 1,000 meters)

(1) The ship's average speed over the 9 kilometers was greater than 55 meters per minute.
(2) The ship's average speed over the 9 kilometers was less than 60 meters per minute.

Kudos for a correct solution.

MANHATTAN GMAT OFFICIAL SOLUTION:

Notice that the statements provide rates in meters per minute. A good first step here is to figure out how fast the ship would have to travel to cover 9 kilometers in 3 hours. Create an RTD chart, and convert kilometers to meters and hours to minutes:

180r= 9,000
r= 50

The question asks whether the ship traveled 9 kilometers in less than 3 hours. The ship must travel faster than 50 meters/min to make it in less than 3 hours. Therefore, the question is really asking, is r > 50?

(1): SUFFICIENT: If the average speed of the ship was greater than 55 meters per minute, then r > 55. Thus, r is definitely greater than 50.

(2): INSUFFICIENT: If the average speed of the ship was less than 60 meters per minute, then r < 60. This is not enough information to guarantee that r > 50.

Answer: A.

Attachment:
2015-06-29_1819.png

Hi Bunuel -

if rate > 50 kms/hour (chosen randomly) and time < 2 hours (randomly)

will distance be >100 kms or will distance < 100 kms ?

When the signs are direction ally opposite - what are the rules for the multiplication
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