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For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range

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For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range  [#permalink]

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New post 09 Mar 2017, 21:41
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For integers x and y, if \(x<a<2\) and \(-2<b<y\) , is 1 contained in the range of ab?

1) \(x=1\)

2) \(x < y\)

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Re: For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range  [#permalink]

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New post 12 Mar 2017, 04:11
ziyuen wrote:
For integers x and y, if \(x<a<2\) and \(-2<b<y\) , is 1 contained in the range of ab?

1) \(x=1\)

2) \(x < y\)


Hi,

Lowest of two in ab will be 2*-2=-4...
To find if 1 is there, we have to find if the higher range is above 1..
The other three possibilities for highest ab are x*(-2), 2y and xy....
A) So if x is -ive, x*-2 will be POSITIVE and > or = 2.....Ans will be YES
B) if y is POSITIVE 2*y will be >or =2....Ans will be again YES

Let's see the statements..
(1) x=1...
x as positive ALONE does not answer the Q, it will require y to be POSITIVE..
Insufficient


(2) x<y..
If y is positive, answer from (B) will be YES..
If y is NEGATIVE or 0, x will also be NEGATIVE, so from (A), and will be YES..
Thus sufficient


B
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Re: For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range  [#permalink]

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New post 12 Mar 2017, 04:20
For integers x and y, if x<a<2x<a<2 and −2<b<y−2<b<y , is 1 contained in the range of ab?

1) x=1x=1

2) x<y

(1) x=1
x as positive ALONE does not answer the Q, it will require y to be POSITIVE..
Insufficient
(2) x<y
If y is positive, answer from (B) will be YES..
If y is NEGATIVE or 0, x will also be NEGATIVE, so from (A), and will be YES..
sufficient
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Re: For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range &nbs [#permalink] 12 Mar 2017, 04:20
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For integers x and y, if x<a<2 and -2<b<y, is 1 contained in the range

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