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Joined: 03 Oct 2013
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Location: India
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Re: given x≠y, what is the value of x^2y-xy^2
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17 Feb 2021, 23:31
Simplifying the following expression, we have
\(\frac{xy(x - y)}{\frac{1}{x} - \frac{1}{y}} = \frac{xy(x - y)}{\frac{y - x}{xy}} = -(x^2y^2) = - (xy)^2\)
So all we need is the value of x and y or the value of xy to answer the question
Statement 1: xy = 6. This is sufficient to answer the question as shown above. Answer Options could be A or D
Statement 2: x - y = 1. This statement is insufficient as we can only derive the fact that x = y + 1, and we can get multiple answers for the same.
Option A
Arun Kumar
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