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Bunuel
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ThatDudeKnows
Bunuel
How many positive three-digit positive integers are multiples of 6, 9 and 7?

(A) 3
(B) 4
(C) 6
(D) 7
(E) 8

Multiples of 7 and 9 occur only once every 63 integers. Let's just list them out.

126
189
252
315
378
441
504
567
630
693
756
819
882
945

Of those, none of the odds is divisible by 6, and all of the evens are.

That's seven.

Answer choice D.

Hey ThatDudeKnows, what if we take the LCM of all 3 which is 126 and then we see there are only 7 multiples of 126 less than a 1000
Is this approach ok and will work for all similar problems? Or something wrong with this?
Thanks


That's totally fine!! :thumbsup: :thumbsup:

If you're comfortable and confident with deploying formulas and rules, that's a-okay! If you like to see that the formula/rule functions the way you expected, it never hurts to give yourself examples to be totally sure.
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IMO Option D is the answer. The LCM of 6, 9 and 7 is 126.

The multiples of LCM will be what can evenly divide 6,9 and 7.

125*8 =1000
Therefore 126*8 = 1008
and 126*7 = 882

Therefore, option D is the answer.
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